如何在模拟器中获取 ios 中的当前位置？

Question

我正在使用此代码获取当前位置，但没有得到正确的结果来获取模拟器中的当前位置，

-(void)initLocationManager
{
    locationManager=[[CLLocationManager alloc] init];
    locationManager.delegate = self;
    if (([locationManager respondsToSelector:@selector(requestWhenInUseAuthorization)]))
    {
        [locationManager requestWhenInUseAuthorization];
    }
    locationManager.desiredAccuracy = kCLLocationAccuracyBest;
    locationManager.distanceFilter = kCLDistanceFilterNone;

    //[locationManager requestWhenInUseAuthorization];
    // [locationManager startMonitoringSignificantLocationChanges];
    [locationManager startUpdatingLocation];

}

-(void)locationManager:(CLLocationManager *)manager didUpdateLocations:(NSArray *)locations
{
    CLLocation* location = [locations lastObject];
    //   NSDate* eventDate = location.timestamp;
    // NSTimeInterval howRecent = [eventDate timeIntervalSinceNow];

    latitud = location.coordinate.latitude;
    longitud = location.coordinate.longitude;
    NSLog(@"%f,%f",latitud,longitud);
    [locationManager stopUpdatingLocation];

}

请告诉我如何获得这个当前位置，我从早上开始就累了。请帮帮我

Answer 1

使用以下步骤创建 GPX 文件：

• 进入项目--> 添加新的--> iOS --> 资源并选择GPX文件

• 现在您需要在 GPX 文件中编写如下小代码：

---

<!--
        Provide one or more waypoints containing a latitude/longitude pair. If you provide one
        waypoint, Xcode will simulate that specific location. If you provide multiple waypoints,
        Xcode will simulate a route visitng each waypoint.
 -->
<wpt lat="37.331705" lon="-122.030237">  // here change lat long to your lat long
     <name>Cupertino</name> // here set name 

     <!--   
            Optionally provide a time element for each waypoint. Xcode will interpolate movement
            at a rate of speed based on the time elapsed between each waypoint. If you do not provide
            a time element, then Xcode will use a fixed rate of speed.

            Waypoints must be sorted by time in ascending order.
      -->
     <time>2014-09-24T14:55:37Z</time>
</wpt>

• 现在去编辑架构

• 然后选择run 并在Option 菜单中选择如下所示出现我们的GPX 文件选择并运行并关闭：

现在您可以在 GPX 文件中获取添加的 lat long 的位置。

更新

以下是启用位置的代码：

• 在 info.plist 中，您需要设置 NSLocationWhenInUseUsageDescription 和 NSLocationWhenInUseUsageDescription 关于定位服务。

现在是你的 .h 类

#import <UIKit/UIKit.h>
#import <CoreLocation/CoreLocation.h>
@interface ViewController : UIViewController<CLLocationManagerDelegate>
{

    __weak IBOutlet UILabel *lblLat;
    __weak IBOutlet UILabel *lblLong;
}
@property(strong,nonatomic) CLLocationManager *locationManager;
@end

.M 类

- (void)viewDidLoad {
    [super viewDidLoad];

    self.locationManager = [[CLLocationManager alloc] init];
    [self.locationManager requestWhenInUseAuthorization];


    self.locationManager.delegate = self;
    self.locationManager.desiredAccuracy = kCLLocationAccuracyBest;

    [self.locationManager startUpdatingLocation];
    // Do any additional setup after loading the view, typically from a nib.
}

- (void)didReceiveMemoryWarning {
    [super didReceiveMemoryWarning];
    // Dispose of any resources that can be recreated.
}
- (void)locationManager:(CLLocationManager *)manager didFailWithError:(NSError *)error
{
    NSLog(@"didFailWithError: %@", error);
    UIAlertView *errorAlert = [[UIAlertView alloc]
                               initWithTitle:@"Error" message:@"Failed to Get Your Location" delegate:nil cancelButtonTitle:@"OK" otherButtonTitles:nil];
    [errorAlert show];
}

- (void)locationManager:(CLLocationManager *)manager didUpdateToLocation:(CLLocation *)newLocation fromLocation:(CLLocation *)oldLocation
{
    NSLog(@"didUpdateToLocation: %@", newLocation);
    CLLocation *currentLocation = newLocation;

    if (currentLocation != nil) {
        lblLat.text = [NSString stringWithFormat:@"%.8f", currentLocation.coordinate.latitude];
        lblLong.text = [NSString stringWithFormat:@"%.8f", currentLocation.coordinate.longitude];
    }
}

工作演示代码：https://github.com/nitingohel/UserCurrentLocation_Objc

Answer 2

在模拟器中你需要在调试区选择位置模拟

或在编辑方案中

或者您可以添加自己的带有坐标的 GPX 文件

Answer 3

模拟器无法直接获取当前位置，需要到模拟器Debug>location>custom的位置，设置经纬度。