【问题标题】：Filter JSON data (containing object array) in nodejs在nodejs中过滤JSON数据（包含对象数组）
【发布时间】：2018-04-20 06:56:10
【问题描述】：

** 以下是我的 JSON 数据

我想使用 nodejs 过滤并拥有 rulescore > 0 的数据

{
 "https://www.google.com":{
   "sitescore":99,
       "rules":[
            {
        "rulename":"rule1","rulescore":0,"description":"rules1 descript"},
            {
        "rulename":"rule2","rulescore":1,"description":"rules2 descript"},
            {
        "rulename":"rule3","rulescore":0,"description":"rules3 descript"}
            ]
           }
}

我想使用 nodejs 过滤并拥有 rulescore > 0 的数据

【问题讨论】：

到目前为止，您尝试过哪些filters？如果您需要帮助调试，请发布您的代码
首先将 JSON 转换为 javascript 对象，稍后你会感谢我的
How to filter an array in javascript?的可能重复
我尝试使用 npm 包下划线，但我不知道该怎么做
@VedaVyas 当数组有filter 方法时，你为什么还要费心下划线？见Array.prototype.filter

标签： javascript json node.js

【解决方案1】：

对rules数组使用filter操作，得到rulescore大于0的规则。

var dataObj = {
 "sitename":{
   "sitescore":99,
   "rules":[
     {
       "rulename":"rule1","rulescore":0,"description":"rules1 descript"
     },
     {
       "rulename":"rule2","rulescore":1,"description":"rules2 descript"
     },
     {
       "rulename":"rule3","rulescore":0,"description":"rules3 descript"
     }
   ]
 }
};

var res = dataObj.sitename.rules.filter((rule) => rule.rulescore > 0);
console.log(res);

【讨论】：

【解决方案2】：

ES6

可以使用filter()数组方法。

演示

const data = {
    "sitename": {
        "sitescore": 99,
        "rules": [{
            "rulename": "rule1",
            "rulescore": 0,
            "description": "rules1 descript"
        }, {
            "rulename": "rule2",
            "rulescore": 1,
            "description": "rules2 descript"
        }, {
            "rulename": "rule3",
            "rulescore": 0,
            "description": "rules3 descript"
        }]
    }
};


console.log(data.sitename.rules.filter(({rulescore}) => rulescore > 0));

.as-console-wrapper { max-height: 100% !important; top: 0; }

【讨论】：

【解决方案3】：

    var dataObj={
         "https://www.google.com":{
        "sitescore":99,
         "rules":[
                {
             "rulename":"rule1","rulescore":0,"description":"rules1 descript"},
              {
             "rulename":"rule2","rulescore":1,"description":"rules2 descript"},
               {
             "rulename":"rule3","rulescore":0,"description":"rules3 descript"}
             ]
             }
       };

      var res = (dataObj["https://www.google.com"]).rules.filter(rule => 
   rule.rulescore > 0);
       console.log(res);

【讨论】：