我认为这是设计有缺陷的症状。看起来您正在尝试查找 3 名玩家的分数。您正在循环 3 行,但尝试在每次迭代中访问所有 3 名玩家的数据。相反,您应该在各自的迭代中访问每个玩家的数据并建立一个玩家数据列表。
为了直接回答您的问题,在第 1 次迭代中,您尝试访问元素 0、1 和 2,但 $rows 仅填充了 0。
+-----------+-------------------------+--------------------------+
| Iteration | You're trying to access | You only have access to |
+-----------+-------------------------+--------------------------+
| 1 | 0,1,2 | 0 |
| 2 | 0,1,2 | 0,1 |
| 3 | 0,1,2 | 0,1,2 |
+-----------+-------------------------+--------------------------+
例子
<?php
// Turn on error reporting
ini_set('display_errors', 1);
ini_set('display_startup_errors', 1);
error_reporting(E_ALL);
// Show MySQL errors as PHP exceptions
mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
include '../connect_database.php';
// Build up this list inside the loop.
$scores = [];
$sql = "SELECT score FROM dailyscore Where Id IN (1,2,3)";
date_default_timezone_set('America/New_York');
$result = $connect->query($sql);
while ($row = mysqli_fetch_assoc($result)){
// You only have access to a single $row here.
// Build up an array of the data you want instead of tring to access "other rows"
$scores[] = $row['score'];
}
// Now, you can use $scores to build $list... or build $list inside the loop.
?>
编辑
您介意向我展示如何将数组结果分配给的示例吗
像这样的东西? $list['scores'] = array('data' => $id1, 'data1'
=> $id2, 'data2' => $id3);
<?php
// Turn on error reporting
ini_set('display_errors', 1);
ini_set('display_startup_errors', 1);
error_reporting(E_ALL);
// Show MySQL errors as PHP exceptions
mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
include '../connect_database.php';
// Build up this list inside the loop.
$scores = [];
$counter = 0;
$sql = "SELECT score FROM dailyscore Where Id IN (1,2,3)";
date_default_timezone_set('America/New_York');
$result = $connect->query($sql);
while ($row = mysqli_fetch_assoc($result)){
$keyName = 'data';
if ($counter > 0) {
$keyName = 'data' . $counter;
}
$scores[$keyName] = $row['score'];
$counter++;
}
$list['scores'] = $scores;
echo json_encode($list);