【发布时间】:2021-08-08 14:49:12
【问题描述】:
我有三个彼此相邻的画布和一个我想在其中两个上绘制的图像。下面的代码在一个画布上绘制图像两次(根据需要),但不会在另一个画布上绘制它,如下面的屏幕截图所示。
通过调试,我确定c1.drawImage(img, x, y, 50, 50); 行运行(这可以在输出“here”的控制台中看到)。这应该将图像绘制到第二个画布上,但事实并非如此。
JsFiddle:https://jsfiddle.net/3xnpys9m/1/
var area0 = document.getElementById("area-0");
var area1 = document.getElementById("area-1");
var area2 = document.getElementById("area-2");
var c0 = area0.getContext("2d");
var c1 = area1.getContext("2d");
var c2 = area2.getContext("2d");
// Set height and width of areas
area0.width = area1.width = area2.width = 150;
area0.height = area1.height = area2.height = 150;
var arr; // holds all positions
var img;
populate();
function populate() {
arr = [
[0, 0],
[40, 40],
[170, 0]
];
img = new Image();
img.onload = function() {
// for each position in array
for (var i = 0; i < arr.length; i++) {
var x = arr[i][0]; // x position
var y = arr[i][1]; // y position
draw(x, y);
}
}
img.src = "https://upload.wikimedia.org/wikipedia/commons/thumb/e/e0/SNice.svg/1200px-SNice.svg.png";
}
// Draw onto canvas
function draw(x, y) {
var area;
// Work out which area to draw in
if (x < area0.width + 1) {
area = 0;
} else if (x < (area0.width * 2) + 1) {
area = 1;
} else if (x < (area0.width * 3) + 1) {
area = 2;
}
// Draw onto correct area
if (area == 0) {
c0.drawImage(img, x, y, 50, 50);
} else if (area == 1) {
console.log("here");
c1.drawImage(img, x, y, 50, 50);
} else if (area == 2) {
c2.drawImage(img, x, y, 50, 50);
}
}
#canvases {
width: 470px;
}
<div id="canvases">
<canvas id="area-0"></canvas>
<canvas id="area-1"></canvas>
<canvas id="area-2"></canvas>
</div>
我认为问题可能与在多个画布上绘制相同的图像有关,但是从数组 arr 中删除前两项并不能解决问题。
【问题讨论】:
标签: javascript html html5-canvas