【发布时间】:2019-09-30 14:26:22
【问题描述】:
我通过适配器的 add() 和 clear() 从适配器对象中添加和删除值,它们正在向列表中删除和添加元素,该列表未从适配器内部的任何位置引用。我有 orig 列表,它位于适配器外部,并且从适配器内部引用到不变的外部引用,而在适配器内部我只引用了一个 new 列表,我使用旧的具有相同对象的原始列表。为什么新列表会影响旧列表?
class LanguageItemArrayAdapter extends ArrayAdapter<com.anysoftkeyboard.ui.settings.LanguageItem>{
private Context mContext;
private final ArrayList<com.anysoftkeyboard.ui.settings.LanguageItem> origList = new ArrayList<com.anysoftkeyboard.ui.settings.LanguageItem>();
private final ArrayList<com.anysoftkeyboard.ui.settings.LanguageItem> filteredList = new ArrayList<com.anysoftkeyboard.ui.settings.LanguageItem>();
LanguageItemArrayAdapter(@NonNull Context context, @LayoutRes ArrayList<com.anysoftkeyboard.ui.settings.LanguageItem> list, ArrayList<com.anysoftkeyboard.ui.settings.LanguageItem> filteredList){
super(context, 0, filteredList);
mContext = context;
origList.addAll(list); //THIS WORKS WELL.
//THIS BREAKS EVERYTHING ->
//origlist = list;
}
public void fillData(){
filteredList.addAll(origList);
notifyDataSetChanged();
}
@Override
public View getView(int position, View convertView, @NonNull ViewGroup parent) {
View listItem = convertView;
if (listItem == null)
listItem = LayoutInflater.from(mContext).inflate(R.layout.languages_list_row, parent, false);
com.anysoftkeyboard.ui.settings.LanguageItem currentItem = filteredList.get(position);
TextView title = listItem.findViewById(R.id.title);
title.setText(currentItem.getTitle());
return listItem;
}
private Filter myFilter = new Filter() {
@Override
protected FilterResults performFiltering(CharSequence constraint) {
FilterResults filterResults = new FilterResults();
ArrayList<com.anysoftkeyboard.ui.settings.LanguageItem> tempList=new ArrayList<com.anysoftkeyboard.ui.settings.LanguageItem>();
//constraint is the result from text you want to filter against.
//objects is your data set you will filter from
if(constraint != null) {
int length= origList.size();
int i=0;
while(i<length){
LanguageItem item= origList.get(i);
if(item.toString().toUpperCase().contains(constraint.toString().toUpperCase())) {
tempList.add(item);
}
i++;
}
//following two lines is very important
//as publish result can only take FilterResults objects
filterResults.values = tempList;
filterResults.count = tempList.size();
}
return filterResults;
}
//HERE ARE THE AFFECTING METHODS:
@Override
protected void publishResults(CharSequence constraint, FilterResults results) {
filteredList.clear();
clear(); //******THIS METHOD REMOVES THE VALUES from origList as well******
filteredList.addAll((Collection<? extends LanguageItem>) results.values);
notifyDataSetChanged();
//*****THIS ADDS VALUES TO ORIG LIST AS WELL. WHY?*****
for(LanguageItem item: filteredList)
add(item);
}
};
@Override
public Filter getFilter() {
return myFilter;
}
}
为什么我只更改过滤后的列表时会编辑原始列表?
编辑:
ArrayAdapter<com.anysoftkeyboard.ui.settings.LanguageItem> adapter = new LanguageItemArrayAdapter(getContext(), simpleLanguageItems, simpleLanguageItems);
((LanguageItemArrayAdapter) adapter).fillData();;
(我知道修复,但我不明白原因 - 如果您像我一样在自定义适配器过滤器上遇到问题,修复在下面的代码中。)
【问题讨论】:
-
在构造函数中,我期望
this.filteredList = filteredList;或者更好地删除字段filteredList,因为它似乎是父类。代码似乎有点值得重新设计。 -
@Joop Eggen 如果你知道答案,请告诉我,如果需要我会重写编译并再次编辑。
-
能否分享一下你如何构造参数
list和filteredList的代码,以及你是如何调用LanguageItemArrayAdapter构造函数的代码? -
@VitaliPom 对不起,对我来说太混乱了。我不一定比你“好”。
-
@Joop ♥ 很酷对不起。我有 2-3 个机器人会否决我在这里写的每一个问题,今天又发生了。我以为它又是其中之一。抱歉,是的,代码有点脏,需要清理。同时一般来说没关系,因为这个问题很有趣。我再次道歉,我发现好人很少。是的,当我在 repo 中修复时,我也会在这里修复。非常感谢!!!!
标签: java android android-arrayadapter deep-copy