java中数组中对象的验证

Question

如何使用另一个类中的对象验证一个类中的数组。 我正在为一个钓鱼比赛做项目，我有一个类别允许的物种，但必须在另一个类别中进行捕获。

#MAIN CLASS#
    Fish bass       = new Fish("Bass",      14, 20);
    Fish catfish    = new Fish("Catfish",   12, 30);
    Fish trout      = new Fish("Trout",     15, 12);
    Fish walleye    = new Fish("Walleye",   10, 15);
    fishList.add(bass);
    fishList.add(catfish);
    fishList.add(trout);
    fishList.add(walleye);






##class Fish##
 {
    //attributes:
    String speciesAllowed;
    double sizeLimit;
    int bagLimit;

//constructors:
Fish()
{
    speciesAllowed = " ";
    sizeLimit = 0.0;
    bagLimit = 0;

}// end constructor w/o argument
Fish(String speciesAllowed, double sizeLimit, int bagLimit)
{
    this.speciesAllowed = speciesAllowed;
    this.sizeLimit = sizeLimit;
    this.bagLimit = bagLimit;


}//end constructor w/ argument 

###class Tournament extends Fish###
{
//attributes:
String ssn;
String species;
double size;
int bag;
double weight;

//------------------------------------------------------------------------
//constructors
Tournament()
{
    super();
    ssn = " ";
    species = " ";
    size = 0.0;
    bag = 0;
    weight = 0.0;

}//end constructor w/0 argument
Tournament(String speciesAllowed, double sizeLimit, int bagLimit, String ssn, String species, double 
 size, int bag, double weight)
{
    super(speciesAllowed, sizeLimit, bagLimit);
    this.ssn = ssn;
    this.species = species;
    this.size = size;
    this.bag = bag;
    this.weight = weight;

}//end constructor w/ argument
//-------------------------------------------------------------------------
void getCatch()
{
    String input = " ";
    boolean valid = false;
    input = JOptionPane.showInputDialog("Enter SSN: ");
    valid = checkSSN(input);
    while(!valid)
    {
        input = JOptionPane.showInputDialog("Invalid SSN...Please re-enter SSN: ");
        valid = checkSSN(input);
    }
    ssn = input;
    input = JOptionPane.showInputDialog("Enter species of the catch: ");
    //valid = checkSpecies(input);
    while(!valid)
    {
        input = JOptionPane.showInputDialog("Sorry that fish is not allowed ");
        //valid = checkSpecies(input);
    }
    species = input;
    //engHours = Integer.parseInt(input);
}//end getBOAT()
//-------------------------------------------------------------------------
void dispTournament()
{
    JOptionPane.showMessageDialog(null, "SSN            : " + ssn       + "\n" +
                                        "Species        : " + species   + "\n" +
                                        "Size           : " + size      + "\n" +
                                        "Bag            : " + bag       + "\n" +
                                        "Weight         : " + weight    + "\n");
}//end dispTournament
//-------------------------------------------------------------------------
boolean checkSSN(String input)
{
    if(input.length() != 9 )
        return false;
    else
        for(int i = 0; i < input.length(); i++)
        {
            if(!Character.isDigit(input.charAt(i)))
                return false;

        }
    return true;
boolean checkSpecies(String input)
{
    String allowed1 = "bass";
    String allowed2 = "trout";
    String allowed3 = "walleye";
    String allowed4 = "catfish";

    for(int i = 0; i < input.length(); i++)
    {
        if(input(i).equalsignorecase(<Fish>speciesAllowed))                 
            return false;
    }
    return true;
}//end checkSpecies

不确定需要多少帮助我的问题与布尔 checkSpecies 相关。我如何将它与 Fish 类中的 speciesAllowed 进行比较。因此，这些是用户可以输入的唯一 Fish。

不，这不是整个程序，这只是我需要帮助的 sn-ps。谢谢。

Answer 1

如果我理解正确的话，Fish 只允许 4 种可能的种类：

Fish bass       = new Fish("Bass",      14, 20);
Fish catfish    = new Fish("Catfish",   12, 30);
Fish trout      = new Fish("Trout",     15, 12);
Fish walleye    = new Fish("Walleye",   10, 15);

在checkSpecies 中，有一个用户输入验证。

boolean checkSpecies(String input)
{
    String allowed1 = "bass";
    String allowed2 = "trout";
    String allowed3 = "walleye";
    String allowed4 = "catfish";

    for(int i = 0; i < input.length(); i++)
    {
        if(input(i).equalsignorecase(<Fish>speciesAllowed))                 
            return false;
    }
    return true;
}

无需遍历input。我假设input 是鱼，必须对其进行验证。相反，您可以检查input 是否存在于允许列表中，例如：

return ALLOWED_SPECIES_LIST.contains(input.toLowerCase())

ALLOWED_SPECIES_LIST 可能类似于
Arrays.asList(allowed1,allowed2,allowed3,allowed4) 如果你想使用定义的Fist，已经有fishList我们可以使用：

return fishList.stream().map(Fish::speciesAllowed).anyMatch(input);

或没有流：

for(String fish: fishList) {
  if (fish.speciesAllowed.equals(input)){
     return true; 
  }
}
return false; 
}

我希望这会有所帮助。