如何检查 NSDictionary 中的值和整数值是否相同？答案

【问题标题】：How can i check the value from NSDictionary and integer values are same?如何检查 NSDictionary 中的值和整数值是否相同？
【发布时间】：2013-03-25 10:02:03
【问题描述】：

我有一个字典，其中的值如图所示，我有一个整数值的 book id 。如何检查 bookid 是否匹配？

这是我的检查代码

NSMutableDictionary *plistdictionary = [[NSMutableDictionary alloc]initWithContentsOfFile:metaDataPath];
NSMutableArray *notes=[plistdictionary objectForKey:@"usernotes"];
NSLog(@"notes value %@",notes);
NSArray *CollectingBookid=[[NSArray alloc]init];
CollectingBookid=[notes valueForKey:@"bookid"];
NSArray *CollectingPages=[[NSArray alloc]init];
CollectingPages=[notes valueForKey:@"pagenumber"];
NSArray *CollectingNotes=[[NSArray alloc]init];
CollectingNotes=[notes valueForKey:@"notes"];
NSLog(@"collection of book id%@",CollectingBookid);
NSString *bookid=@"95";
NSString *page=@"1";
int c=[CollectingBookid count];
for(int i=0;i<c;i++)
{
    NSString *singleBookids=[CollectingBookid objectAtIndex:i];
    NSString *singlePage=[CollectingPages objectAtIndex:i];
    if([singleBookids isEqualToString:bookid])
        {
            if([singlePage isEqualToString:page])
            {
                NSMutableArray *CompleteUserNotes=[[NSMutableArray alloc]init];
                CompleteUserNotes=[CollectingNotes objectAtIndex:i];
                NSLog(@"Selected Notes%@",CompleteUserNotes);
            }
        }
}

【问题讨论】：

为什么 bookid 是 pList 中的字符串？您想将整数与整数进行比较吗？或者你想比较字符串和字符串？
如何在字典中添加整数值？
这些与您的图片不匹配： NSArray *CollectingBookid=[[NSArray alloc]init]; CollectingBookid=[notes valueForKey:@"bookid"]; NSArray *CollectingPages=[[NSArray alloc]init]; CollectingPages=[notes valueForKey:@"pagenumber"]; NSArray *CollectingNotes=[[NSArray alloc]init]; CollectingNotes=[notes valueForKey:@"notes"];

标签： ios xcode nsarray plist nsdictionary

【解决方案1】：

创建谓词并通过过滤数组找到userNote

/*As your plist has bookId as string its taken as string. 
But if you have bookId as integer before checking 
convert it to string for predicate to work*/
NSInteger bookId = 92;
NSString *bookIdString = [NSString stringWithFormat:@"%d",bookId];

NSInteger pageNumber = 12;
NSString *pageNumberString = [NSString stringWithFormat:@"%d",pageNumber];

NSPredicate *predicate = [NSPredicate predicateWithFormat:@"bookid == %@ AND pagenumber == %@",bookIdString,pageNumberString];

//filteredUserNotes will have all notes matching bookId
NSArray *filteredUserNotes =  [notes filteredArrayUsingPredicate:predicate];

//Assuming you only has one entry for bookId and you want a single one
NSDictionary *userNote = [filteredUserNotes lastObject];

【讨论】：

@Naveen 你想找到一个与 bookId rite 匹配的 userNote 项目。在此代码中，您创建一个谓词，它将找到 bookId 与您在谓词中提供的匹配的笔记。在过滤结果是数组时，然后您获取该结果并执行您想要的操作
但我想要页码和 bookid 匹配！！
@Naveen 我已经编辑了代码。如果有任何问题，请告诉我。
如果我给出我的输入而不是你的硬编码 bookid 和页码，你说我不需要检查所有条件而是我可以使用谓词 thaere？
@Naveen 是的，你是对的。我硬编码这些值只是为了向您展示。

【解决方案2】：

您使用字符串格式进行正确比较。

如果您想与整数进行比较，请使用以下代码：

int bookid=95;
int page=1;
int c=[CollectingBookid count];
for(int i=0;i<c;i++)
{
    NSString *singleBookids=[CollectingBookid objectAtIndex:i];
    NSString *singlePage=[CollectingPages objectAtIndex:i];
    if([singleBookids intValue]==bookid)
    { 
        if([singlePage intValue]==page)
        {
            NSMutableArray *CompleteUserNotes=[[NSMutableArray alloc]init];
            CompleteUserNotes=[CollectingNotes objectAtIndex:i];
            NSLog(@"Selected Notes%@",CompleteUserNotes);
        }
    }
}

【讨论】：

【解决方案3】：

我在记事本里写这个。对可能的错误深表歉意。

 NSMutableDictionary *plistdictionary = [[NSMutableDictionary alloc]initWithContentsOfFile:metaDataPath];
NSMutableArray *notes=[plistdictionary objectForKey:@"usernotes"];
int bookid = 95;
int page = 1;
for (NSDictionary *collectingObject in notes)
{
    int collectingBookid = [[collectingObject objectForKey:@"bookid"] intValue];
    int collectingPageid = [[collectingObject objectForKey:@"pagenumber"] intValue];
    if (collectingBookid == bookid && collectingPageid == page)
    {
        NSString *collectingNote = [collectingObject objectForKey:@"notes"];
        NSLog(@"Note is: %@", collectingNote);
    }
}

【讨论】：

如何将整数转换为字符串？
int number = 100500; NSString *stringFromInteger = [NSString stringWithFormat:@"%d", number];

【解决方案4】：

你可以用它来比较整数值

[singleBookids intValue]==[bookid intValue];

【讨论】：