php：如何在段落中查找字符串答案

【问题标题】：php: How to find a string in a paragraphphp：如何在段落中查找字符串
【发布时间】：2013-05-31 07:00:29
【问题描述】：

假设我有：

$strPar = "This is a simple paragraph that we will use for the questioning";
$strFindMe = "that";

如何检查$strPar 是否包含$strFindMe？

【问题讨论】：

标签： php string variables character

【解决方案1】：

最快的方法是使用strpos:

  $exists = strpos($strPar, $strFindMe);
  if ($exists !== false) {
    // substring is in the main string
  }

【讨论】：

@BartFriederichs 是否必须使用!== false ！
先生，另一个问题，我如何用“|”替换新行

【解决方案2】：

试试这样的

if (false !== strpos($strPar, $strFindMe ) )

【讨论】：

为什么你需要false !== ，因为它返回布尔值？
它返回的位置，如果它在字符串的开头将是0，这将评估为假。

【解决方案3】：

$string = "This is a strpos() test";
$pos = strpos($string, "i", 3);

    if ($pos === false) {
     print "Not found\n";
}else{
     print "Found at $pos!\n";
}

【讨论】：

【解决方案4】：

<?php
$strPar = "This is a simple paragraph that we will use for the questioning";
$strFindMe   = "that";
$pos = strpos($strPar, $strFindMe);

// Note our use of ===.  Simply == would not work as expected
// because the position of 'a' was the 0th (first) character.
if ($pos === false) {
    echo "The string '$findme' was not found in the string '$mystring'";
} else {
    echo "The string '$findme' was found in the string '$mystring'";
    echo " and exists at position $pos";
}
?>

【讨论】：

【解决方案5】：

检查strpos()函数，区分大小写！

if( strpos($strPar, $strFindMe) ) {  //it return a boolean value
   echo "String Found";
}

【讨论】：

【解决方案6】：

$strPar = "This is a simple paragraph that we will use for the questioning";
$strFindMe = "THAT";//Find the position of the first occurrence of a case-insensitive substring in a string
$exists = strpos($strPar, $strFindMe);
  if ($exists !== false) {
    // substring is in the main string
  }

【讨论】：