PHP：将两个多维度数组合并为一个

Question

我尝试创建一个多维数组 ($list)，它应该如下所示：

[
  {"uri": "http://www.example.com/1", "traverseCount": "1"},
  {"uri": "http://www.example.com/2", "traverseCount": "1"},
  {"uri": "http://www.example.com/3", "traverseCount": "1"}
]

但是，我不知道如何从以下数据中最好地实现这一目标。 这两个数据源来自两个If-Else 并尝试为每个案例创建一个多维数组。但是，最后，我想生成一个多维数组，它将两个多维数组与连续有序键结合起来。 （所以，从上面的例子来看，http://www.example.com/1 和 http://www.example.com/2 来自第一个 Else-If 的结果，http://www.example.com/3 来自第二个 Else-If）。棘手的一点是foreach 里面有Else-If。

// Create an empty multidimentional array to accommodate 2 datasets (2 If-Else cases) below:
$traverseCount = 1;
$list = array(
  array(),
  array()
);
//This is the first data source. Say, it returns 2 URIs when doing the foreach loop:
$match = $graph->resourcesMatching('skos:exactMatch');
if (isset($match) == true && count($match) > 0){
  $graphuris = $match[0]->all('skos:exactMatch');
  echo '<b>skos:exactMatch Links: </b><br>';
  foreach ($graphuris as $uris) {
    $counter = 0;
    $list[$counter][0] = $uris->__toString();
    $list[$counter][1] = $traverseCount;
    $counter++;
    echo '<a href="'.$uris.'" target="_blank">'.$uris.'</a><br>';
  }
}
else {
  echo '<p>No skos:exactMatch found</p>';
}
//This is the second data source, whose multidimensional array should be added to the end of the previous multidimensional array 
$match2 = $graph->resourcesMatching('rdfs:seeAlso');
if (isset($match2) == true && count($match2) > 0){
  $graphuris2 = $match2[0]->all('rdfs:seeAlso');
  echo '<b>rdfs:seeAlso Links: </b><br>';
  foreach ($graphuris2 as $uris2) {
    $counter = 0;
    $list[$counter][0] = $uris2->__toString();
    $list[$counter][1] = $traverseCount;
    $counter++;
    echo '<a href="'.$uris2.'" target="_blank">'.$uris2.'</a><br>';
  }
}
else{
  echo '<p>No rdfs:seeAlso found</p><br>';
}
// $traverseCount is always 1 until here, but it needs to add 1 for the next script to run.
$traverseCount++;

Answer 1

不需要那么复杂。不需要像这样的$counter 就可以添加到数组中。

// Create an empty multidimentional array to accommodate 2 datasets (2 If-Else cases) below:
$traverseCount = 1;

$list = array();
//This is the first data source. Say, it returns 2 URIs when doing the foreach loop:
$match = $graph->resourcesMatching('skos:exactMatch');
if (isset($match) == true && count($match) > 0){
  $graphuris = $match[0]->all('skos:exactMatch');
  echo '<b>skos:exactMatch Links: </b><br>';
  foreach ($graphuris as $uris) {

    $list[] = array('uri'           => $uris->__toString(), 
                    'traversecount' => $traverseCount
                    );

    echo '<a href="'.$uris.'" target="_blank">'.$uris.'</a><br>';
  }
}
else {
  echo '<p>No skos:exactMatch found</p>';
}
//This is the second data source, whose multidimensional array should be added to the end of the previous multidimensional array 
$match2 = $graph->resourcesMatching('rdfs:seeAlso');
if (isset($match2) == true && count($match2) > 0){
  $graphuris2 = $match2[0]->all('rdfs:seeAlso');
  echo '<b>rdfs:seeAlso Links: </b><br>';
  foreach ($graphuris2 as $uris2) {
    $list[] = array('uri'           => $uris2->__toString(), 
                    'traversecount' => $traverseCount
                    );

    echo '<a href="'.$uris2.'" target="_blank">'.$uris2.'</a><br>';
  }
}
else{
  echo '<p>No rdfs:seeAlso found</p><br>';
}
// $traverseCount is always 1 until here, but it needs to add 1 for the next script to run.
$traverseCount++;

我对@9​​87654323@ 有点困惑，因为在两个循环完成之前它似乎不会在您的代码中发生变化。

Answer 2

您总是在每次迭代中将此 $counter 重置为 0。而是将新元素附加到数组：

$list = [];

if () {
    foreach () {
        $list[] = [
            $uris->__toString(),
            $traverseCount
        ];
    }
}

这里我不使用计数器，只是使用$list[] 向数组添加新元素，索引会自动递增。

$uris->__toString() 和 $traverseCount 自动放入 0 和 1 索引

---

我看不到您的 $traverseCount 会发生怎样的变化，因为它在开始时被分配为 1，并且只有在结束时才会增加。