如果 foreach 中的条件知道所有匹配项

Question

我有这个$fields 数组：

Array
(
    [0] => Array
        (
            [field] => Name
            [condition] => 0
            [value] => abc
        )

    [1] => Array
        (
            [input] => Username
            [condition] => 1
            [value] => xyz
        )

    [2] => Array
        (
            [input] => Email
            [condition] => 1
            [value] => xyz@gmail.com
        )
    ...
)

条件 0 等于，条件 1 不等于。我怎样才能注意到所有的匹配项。

如果只有所有条件都匹配，我需要回显一些内容。我的意思是if value is abc for name and value is not xyz for username and value is not xyz@gmail.com for email field.。

foreach( $fields as $field ) {
   if( $field['condition'] == 0 ) {
       if( $field['value'] == 'value_from_input') {
           echo 'something';       
       }
    }
    elseif( $field['condition'] == 0 ) {
      if( $field['value'] == 'value_from_input') {
           echo 'something';       
       }
   } 
}

但这似乎是 OR 条件，如果有任何匹配项，则会有回显。我需要所有条件来匹配。

问候，

Answer 1

将标志设置为真，然后循环遍历数组，当存在不匹配的代码时，将标志设置为假并跳出循环。如果循环后flag仍然为真，则可以确定所有条件都匹配：

$fields = [
    [
        "field" => "Name",
        "condition" => 0,
        "value" => "abc",
    ],
    [
        "field" => "Username",
        "condition" => 1,
        "value" => "abc",
    ],
    [
        "field" => "Email",
        "condition" => 1,
        "value" => "abc",
    ],
];
$success = true;
foreach( $fields as $field ) {
   if ($field["condition"] === 0) {
       $success = false;
       break;
   }
}
if ($success) { 
    echo "All conditions match";
}
else {
    echo "Some conditions don't match";
}

Demo

实际上有很多方法可以做到这一点。另一种是过滤条件不匹配的字段，然后比较每个数组的counts：

$filtered = array_filter($fields, function($el) {
    return $el["condition"] === 0;
});
$success = count($fields) === count($filtered);
if ($success) { 
    echo "All conditions match";
}
else {
    echo "Some conditions don't match";
}