Bash将变量分配给命令输出，该输出将是多个单词字符串的列表[重复]答案

【问题标题】：Bash assigning a variable to a command output which will be a list of multiple word strings [duplicate]Bash将变量分配给命令输出，该输出将是多个单词字符串的列表[重复]
【发布时间】：2022-01-06 05:26:13
【问题描述】：

这是我要运行的脚本

bRules=(`aws s3api get-bucket-lifecycle-configuration --bucket x |  jq '.Rules[]'.ID`)
echo "*** Total number of LifecycleRules ****  ${#bRules[@]}"
for rule in "${bRules[@]}"
do
    echo "Bucket: x, Rule: $rule"
done

实际输出

*** Total number of LifecycleRules ****  6
 Bucket: x, Rule: This
 Bucket: x, Rule: is
 Bucket: x, Rule: Rule-1
 Bucket: x, Rule: This
 Bucket: x, Rule: is
 Bucket: x, Rule: Rule-2

预期输出：

*** Total number of LifecycleRules ****  2
Bucket: x, Rule: This is Rule-1
Bucket: x, Rule: This is Rule-2

需要对我的代码 sn-p 进行哪些更改才能获得所需的输出？我有点迷失了解决这个问题。

【问题讨论】：

标签： arrays string bash variable-assignment

【解决方案1】：

不要依赖命令替换和分词。请改用readarray（或mapfile，如果您愿意）并处理替换。

您的循环也可以简化为单个printf。

readarray -t bRules < <(aws s3api get-bucket-lifecycle-configuration --bucket x | jq '.Rules[]'.ID)
echo "*** Total number of LifecycleRules ****  ${#bRules[@]}"
printf 'Bucket: x, Rule: %s\n' "${bRules[@]}"

阅读Bash Manual。

【讨论】：