【发布时间】:2011-01-06 15:43:07
【问题描述】:
问题在于: 在控制器的 codeigniter 中,我有下一个代码:
$query_not_voted = "SELECT * FROM photos WHERE p_id NOT IN (SELECT distinct p_id FROM p_votes where u_id = ".$this->session->userdata('u_id').") LIMIT ".$this->db->escape_str($segment_url).", ".$config['per_page'];
$q = $this->db->query($query_not_voted);
$data['myphotos'] = $q->result_array();
foreach($data['myphotos'] as $key=>$val)
{
$query_g = "SELECT * FROM users WHERE u_id = (SELECT u_id FROM p_votes WHERE p_id = ".$val['p_id'].")";
$q_2 = $this->db->query($query_g);
$data['allvotess'] = $q_2->result_array();
$query_u = "SELECT * FROM users WHERE u_id = ".$val['u_id']." LIMIT 0, 5";
$q_1 = $this->db->query($query_u);
$data['author'] = $q_1->result_array();
}
所以现在我有了$data['myphotos'],这可以用下一个代码在视图中输出:
<?php foreach ($myphotos as $keys => $myphoto){ ?>
<div id="voteblock">
<div id="voteleft">
<a href="<?php echo base_url().$myphoto['p_small']; ?>" class="preview" title="<?php echo base_url().$myphoto['p_title']; ?>"><img src="<?php echo base_url().$myphoto['p_thumb']; ?>" /></a>
</div>
<?php } ?>
但是如何在最后一个 foreach 循环中输出$data['allvotess']?
我也尝试过,但没有成功。
然后我尝试将结果推入 $data['myphotos'] 并没有好的结果!
那我在做什么???
只需要有人帮我处理foreachloop insite foreachloop!!! 一个星期我都做不到,我什至可以立即支付解决方案!!!
我也在 codeingiter 论坛上发帖,但他们说很简单,link
【问题讨论】:
标签: codeigniter loops foreach