如何创建一种方法来计算数组中的字符

Question

所以我有一个方法可以创建一个由 100 个随机生成的字符组成的数组。

这里是：

//method to generate random character between ch1 and ch2
   public static char getRandomCharacter(char ch1, char ch2)
   {

      return (char) (ch1 + Math.random() * (ch2 -ch1 +1));

   }

//==========================================   

   //method to assign generated characters (between a and z) to a 100 character array
   public static char[] createArray()
   {

      //declare a 100 character array
      char[] character = new char[100];

      //for loop assigning the random characters to the array using getRandomCharacter method
      for (int x = 0; x < character.length; x++)
      character[x] = getRandomCharacter('a', 'z');

      //for loop outputting the characters in the array
      for (int x = 0; x < character.length; x++)
      System.out.println(character[x]);

      return character;

   }

现在我需要创建一个方法来获取 100 个生成的字符，并计算每个元音生成的次数。我被这个困住了。

这是我目前所拥有的：

public static void countArray()
   {

      int vowelA, vowelE, vowelI, vowelO, vowelU, vowelY;
      int elsePlaceHolder = 0;

      for (int x = 0; x < 100; x++)
      {

         if ((createArray()) == ('a'))
         vowelA++;

         else if ((createArray()) == ('e'))
         vowelE++;

         else if ((createArray()) == ('i'))
         vowelI++;

         else if ((createArray()) == ('o'))
         vowelO++;

         else if ((createArray()) == ('u'))
         vowelU++;

         else if ((createArray()) == ('y'))
         vowelY++;

         else
         elsePlaceHolder++;

      }

我相信我使用 for 循环来执行此操作是正确的，但我认为我没有正确执行它。一旦执行，我可以显示使用 int 变量计算元音的次数。 elsePlaceHolder 变量在那里，因为我不知道如何处理 else 语句。

谁能用我的countArray() 方法指出我正确的方向？将不胜感激！

Answer 1

我觉得你应该把上面的代码修改成这个！

public static void countArray()
{

  int vowelA=0, vowelE=0, vowelI=0, vowelO=0, vowelU=0, vowelY=0;
  int elsePlaceHolder = 0;
  char [] arr = new char[100];
  arr=createArray();
  for (int x = 0; x < 100; x++)
  {

     if (arr[x] == 'a')
     vowelA++;

     else if (arr[x] == 'e')
     vowelE++;

     else if (arr[x] == 'i')
     vowelI++;

     else if (arr[x] == 'o')
     vowelO++;

     else if (arr[x] == 'u')
     vowelU++;

     else if (arr[x] == 'y')
     vowelY++;

     else
     elsePlaceHolder++;

  }
  System.out.print(vowelA+" "+vowelE+" "+vowelI+" "+vowelO+" "+vowelU+" "+vowelY);
}

它会起作用的。另外，您还没有初始化那些元音迭代器，但是您已经增加了它们！

Answer 2

您将创建一次数组并计算元素的数量。

char[] chars = createArray();

for(int i = 0; i < chars.length; i++){
    if(chars[i] == 'a')
        increment number of A's
    else if ...
}

我会创建一个大小为 5 的数组，而不是创建 5 个元素，a 是 arr[0]，e 是 arr[1] 等等。

在您的代码中

int[] arr = new int[5];
for(int i = 0; i < chars.length; i++){
    if(chars[i] == 'a')
        arr[0]++;
    else if(chars[i] == 'e')
        arr[1]++;
    //etc
}

Answer 3

    char[] randomc = new char[]{'a','b','i','i','o','u','u','e','e','e','e','e','e','z','b','f'};
    int[] voweltable = new int[] {0, 0, 0, 0, 0, 0}; // Last element is for non-vowels
    for (int i = 0; i <= randomc.length - 1; i++)
    {
        switch(randomc[i])
        {
            case 'a':
                voweltable[0]++;
                break;
            case 'e':
                voweltable[1]++;
                break;
            case 'i':
                voweltable[2]++;
                break;
            case 'o':
                voweltable[3]++;
                break;
            case 'u':
                voweltable[4]++;
                break;
            default:
                voweltable[5]++;
                break;
        }
    }
    for (int i = 0; i <= voweltable.length -1; i++)
        System.out.println(voweltable[i]);

Answer 4

与getRandomCharacter()方法相同，你可以尝试利用字符的int值，并为它构建一个int数组，其大小在ch1和ch2之间，然后增加每次出现的值，然后打印元音的计数，例如：

public static void countArray(char ch1, char ch2, char[] character)
    {
        // Create an array with the letters you want to compare with: vowels
        int[] vowels = {(int) 'a', (int) 'e', (int) 'i', (int) 'o', (int) 'u'};

        // Create the array for the range between the two letters
        int[] dictionary = new int[(int) ch2 - (int) ch1 + 1];

        // Fill up the array with the ocurrence of each character
        for(int i = 0; i < character.length; i++){
            dictionary[((int)character[i] - (int) ch1)]++;
        }

        // Print the occurrence of each vowel
        for(int j = 0; j < vowels.length; j++){
            System.out.println((char) vowels[j] + ": " + dictionary[vowels[j] - (int)'a']);
        }
    }

Answer 5

您好，我只是稍微更改了您的代码。 希望对你有帮助。 看看这个！

private static int vowelA=0;
private static int vowelE=0;
private static int vowelI=0; 
private static int vowelO=0;
private static int vowelU=0;
private static int vowelY=0;
private static int elsePlaceHolder = 0;

public static void main(String[] args) {

        char[] chs = createArray();
        System.out.println("vowelA : "+vowelA);
        System.out.println("vowelE : "+vowelE);
        System.out.println("vowelI : "+vowelI);
        System.out.println("vowelO : "+vowelO);
        System.out.println("vowelU : "+vowelU);
        System.out.println("vowelY : "+vowelY);
}

//method to generate random character between ch1 and ch2
   public static char getRandomCharacter(char ch1, char ch2)
   {

      return (char) (ch1 + Math.random() * (ch2 -ch1 +1));

   }

//==========================================   

   //method to assign generated characters (between a and z) to a 100 character array
   public static char[] createArray()
   {

      //declare a 100 character array
      char[] character = new char[100];

      //for loop assigning the random characters to the array using getRandomCharacter method
      for (int x = 0; x < character.length; x++){
      character[x] = getRandomCharacter('a', 'z');
      countArray(character[x]);
      }
      //for loop outputting the characters in the array
      for (int x = 0; x < character.length; x++)
      System.out.println(character[x]);

      return character;

   }

   public static void countArray(char ch)
   {

         if (ch == ('a')){
         vowelA++;}
         else if (ch == 'e'){
         vowelE++;}
         else if (ch == 'i'){
         vowelI++;}
         else if (ch == 'o'){
         vowelO++;}
         else if (ch == 'u'){
         vowelU++;}
         else if (ch == 'y'){
         vowelY++;}
         else{
         elsePlaceHolder++;}
   }