如何显示数据库中的每一行数据？

Question

我很难在数据库的每一行上显示标题和注释。我想在每个之后显示一行（带有标题和注释） 从页面标题中的表单到显示行数据页面。

下面是我的代码：

// 假设我们有 4 行数据。在我的代码中，我只能显示第一行，因为它一直有第一行的数据。这是因为表单在第一个 php 文件中。然后在我提交表单后，它被定向到这个文件，并且它不断获取第一行。

<?php $con=mysqli_connect("localhost","root","","task");?>
<?php $results = mysqli_query($con, "SELECT * FROM note"); ?>
<?php while ($row = mysqli_fetch_array($results)) { ?>

<?php
$id=$row['id'];
 echo '&nbsp; &nbsp; &nbsp; &nbsp;';
    echo '<button class="call_modal" data-id="$id" style="cursor:pointer;">'. $row['title'] . '</button>';
?>
<?php
}?>
<?php $results = mysqli_query($con, "SELECT * FROM note"); ?>
<?php while ($row = mysqli_fetch_array($results)) { ?>
<div class="note" data-id="<?= $row['id'] ?>">
<div class="modal">
<div class="modal_close close"></div>
<div class="modal_main">

<?php
   echo '<br><br>';

       echo '<div class="padding">'.$row['title'].'';
        echo '<br><br><br><br>';
    echo ''.$row['note'].'</div>';
?>
</div>
</div>
<?php
}?>
<?php
<?php
function test_input($data) { 
  $data = trim($data);
  $data = stripslashes($data);
  $data = htmlspecialchars($data);
  return $data;
} ?>

Answer 1

下面的代码未经测试，但它应该是正确的，并且可以让您更好地了解自己在做什么正确/错误。希望对你有帮助。。

<?php 
$con=mysqli_connect("localhost","root","","task");
$results = mysqli_query($con, "SELECT * FROM note");



while ($row = mysqli_fetch_array($results)) { //starting your data row loop


$id=$row['id'];// you are creating a variable here but not using it two lines down. 
 echo '&nbsp; &nbsp; &nbsp; &nbsp;';
 //YOUR OLD CODE echo '<button class="call_modal" data-id="$id" style="cursor:pointer;">'. $row['title'] . '</button>';
 echo '<button class="call_modal" data-id="$id" style="cursor:pointer;">'. $id . '</button>';// use the variable "$id" that you created here

// You dont need the next two lines, you already did a query and have the data loaded in the "$results" array
/*  $results = mysqli_query($con, "SELECT * FROM note"); 
 while ($row = mysqli_fetch_array($results)) */

?> // close the php tag if you are going to switch to html instead of "echoing html"
/* OLD CODE <div class="note" data-id="<?= $row['id'] ?>"> you were missing the "php" in the php tags */
<div class="note" data-id="<?php echo $id; ?>"> // corrected code
<div class="modal">
<div class="modal_close close"></div>
<div class="modal_main">

<?php //switching back to php so create your open tag again...
   echo '<br><br>';

       echo '<div class="padding">'.$row['title'].'';
        echo '<br><br><br><br>';
    echo ''.$row['note'].'</div>';// you dont NEED the '' before .$row....  unless you want it but its just essentially a blank string
?>
</div>
</div>
<?php
} // ending your "for each data row" here 
?>

<?php
//  PS you're not using this function anywhere unless its in ommited code?
function test_input($data) { 
  $data = trim($data);
  $data = stripslashes($data);
  $data = htmlspecialchars($data);
  return $data;
} ?>

Answer 2

在您的循环中，您使用的是mysqli_fetch_array，它返回一个数组，该数组中的每个元素都包含字段值。

你想要的是mysqli_fetch_assoc，而不是，这将返回一个哈希，然后你可以使用你现在使用它的方式。

另一件事是您不需要在其中有 2 个循环来查询数据库。并且请缩进你的代码，这让你和其他人都很难阅读它。

这是您的代码的更新/清理版本。这个已经测试过了，你可以在我的 Github here 上找到一个带有指令的示例代码。

<?php
$con = mysqli_connect("localhost", "root", "", "task");
$results = mysqli_query($con, "SELECT * FROM note");

while ($row = mysqli_fetch_assoc($results)) {
  $id = $row['id'];
  echo '&nbsp; &nbsp; &nbsp; &nbsp;';
  echo '<button class="call_modal" data-id="' . $id . '" style="cursor:pointer;">'. $row['title'] . '</button>';
  ?>
  <div class="note" data-id="<?= $row['id'] ?>">
    <div class="modal">
      <div class="modal_close close"></div>
        <div class="modal_main">
          <?php
          echo '<br /><br />';
          echo '<div class="padding">' . $row['title'];
          echo '<br /><br /><br /><br />';
          echo $row['note'];
          echo '</div>'
          ?>
        </div>
      </div>
    </div>
  </div>
<?php
}
?>

<?php
function test_input($data) {
  $data = trim($data);
  $data = stripslashes($data);
  $data = htmlspecialchars($data);
  return $data;
}