Python 文本冒险循环

Question

我正在 python 3.3.4 中制作一个非常简单的文本冒险游戏，并且想知道当输入与 a/b 不匹配时是否有任何可能的方法来制作它，它返回到打印命令，其中问题被问到了。

这是我目前拥有的：

import time
import sys
from random import randrange

text = "** Execute Long Intro **"

for c in text:
    sys.stdout.write(c)
    sys.stdout.flush()
    seconds = "0." + str(randrange(1, 2, 1))
    seconds = float(seconds)
    time.sleep(seconds)


time.sleep(1)


obj1 =input('\nDo you \na.) Rest on the ground \nb.) Find a way out of the jungle\n')
if obj1 in ('a'):
    print('You find a comfortable spot on the ground and drift into sleep...')
    time.sleep(.6)
    print('Zzz.\nZzz..\nZzz...')
    time.sleep(3)
    print('You wake to a strange noise, and work your way out of the jungle.') 
    time.sleep(1)

    print('You emerge out of the jungle and walk along the shoreline of a sunny beach')
    time.sleep(1)
    print('** Objective One Completed **')
    time.sleep(2)



elif obj1 == 'b':
    print('You manage to find a path out of the jungle and discover a beach,')
    time.sleep(1)
    print('** Objective One Completed **')
    time.sleep(2)

elif obj1 != ('a','b'):
    print('Uh.')

我们将不胜感激。

Answer 1

使用while 循环：

obj1 = input(...)

while obj1 not in ('a', 'b'):
    obj1 = input("Invalid. Enter again: ")

if obj1 == 'a':
    ...
elif obj1 == 'b':
    ...

Answer 2

您可以尝试使用blessings 库。 安装它：

pip install blessings

而且用法很简单：

from blessings import Terminal
term = Terminal()
print term.clear_bol
print '\t{t.yellow}action{t.normal}|{t.green}Done!{t.normal}'.format(t=term)