SAS Do Loop 正在处理中省略行

Question

我有以下代码。我正在尝试为关键字列表（key_words）测试一个段落（descr）。当我执行此代码时，日志会读取数组的所有变量，但只会测试 do 循环中 20,000 行中的 2 行（do i=1 到 100 等）。有关如何解决此问题的任何建议？

data JE.KeywordMatchTemp1;
  set JE.JEMasterTemp end=eof;
  if _n_ = 1 then do i = 1 by 1 until (eof);
    set JE.KeyWords;
    array keywords[100] $30 _temporary_;
    keywords[i] = Key_Words;
  end;
  match = 0;
  do i = 1 to 100;
    if index(descr, keywords[i]) then match = 1;
  end;
  drop i;
run;

Answer 1

你的问题是你的end=eof放错地方了。

这是一个计算每个SASHELP.CLASS 受访者年龄值“排名”的简单示例。

看看我把end=eof放在哪里。那是因为你需要用它来控制数组填充操作。否则，会发生什么是你的循环 do i = 1 to eof; 并没有真正按照你所说的去做：它实际上并没有在 eof 处终止，因为这永远不会是真的（因为它在 first set 声明）。相反，它会终止，因为您超出了数据集的末尾，而这正是您不想要的。

这就是end=eof 正在做的事情：它会阻止您在数组填充数据集完成时尝试拉一行，这会终止整个数据步骤。每当您看到一个数据步骤恰好在 2 次迭代后终止时，您就可以确信这就是问题所在 - 这是一个非常常见的问题。

data class_ranks;
  set sashelp.class;   *This dataset you are okay iterating over until the end of the dataset and then quitting the data step, like a normal data step.;
  array ages[19] _temporary_; 
  if _n_=1 then do;
    do _i = 1 by 1 until (eof);   *iterate until the end of the *second* set statement;
      set sashelp.class end=eof;  *see here? This eof is telling this loop when to stop.  It is okay that it is not created until after the loop is.;
      ages[_i] = age;
    end;
    call sortn(of ages[*]);   *ordering the ages loaded by number so they are in proper order for doing the trivial rank task;
  end;
  age_rank = whichn(age,of ages[*]);  *determine where in the list the age falls.  For a real version of this task you would have to check whether this ever happens, and if not you would have to have logic to find the nearest point or whatnot.;
run;