如何按两个属性对数组进行排序 - 按字母顺序但最后为空值？

Question

我有一个包含对象的数组。

这些对象有一个 fullname 属性和一个 member-id。

虽然全名始终可用，但如果他或她是潜在成员但尚未注册，则成员 ID 可以为空。

结果应如下所示：

{ id: 1122, name: Adrianna Budzinski }
{ id: 3785, name: Amy Divine }
{ id: 1555, name: Gale Purdue }
{ id: 1920, name: Rex Feng }
{ id: 2010, name: Samella Vizcaino }
{ id: null, name: Bethanie Weaver }
{ id: null, name: Celesta Gullo }
{ id: null, name: Darrick Fort }
{ id: null, name: Edmundo Boulanger }
{ id: null, name: Freddie Lanclos }
{ id: null, name: Gregory Lickteig }
{ id: null, name: Gwendolyn Cuadra }
{ id: null, name: Krystal Brosnahan }
{ id: null, name: Lahoma Pagani }
{ id: null, name: Senaida Risk }
{ id: null, name: Valarie Lopes }

有 id 的成员应该按名称排序在顶部，没有 id 的成员也应该按名称排序。

到目前为止，我实现的是两个独立的排序功能，但我不知道如何合并它们。

let sortedFriends = friends.sort(function(a, b){
  if(a.name < b.name) return -1;
  if(a.name > b.name) return 1;
  return 0;
});

sortedFriends = sortedFriends.sort(function(a, b){
  if(a.id === null) return 1;
  if(b.id === null) return -1;
  if(a.id === b.id) return 0;
  if(a.id < b.id) return -1 ;
  if(a.id < b.id) return 1;
});

Answer 1

您可以使用按组（id 或 null）和名称排序。

var array = [{ id: null, name: 'Darrick Fort' }, { id: null, name: 'Edmundo Boulanger' }, { id: 1122, name: 'Adrianna Budzinski' }, { id: null, name: 'Freddie Lanclos' }, { id: null, name: 'Gregory Lickteig' }, { id: null, name: 'Gwendolyn Cuadra' }, { id: 2010, name: 'Samella Vizcaino' }, { id: null, name: 'Bethanie Weaver' }, { id: null, name: 'Celesta Gullo' }, { id: 3785, name: 'Amy Divine' }, { id: null, name: 'Krystal Brosnahan' }, { id: null, name: 'Lahoma Pagani' }, { id: 1920, name: 'Rex Feng' }, { id: 1555, name: 'Gale Purdue' }, { id: null, name: 'Senaida Risk' }, { id: null, name: 'Valarie Lopes' }];

array.sort(function (a, b) {
    return (a.id === null) - (b.id === null) || a.name.localeCompare(b.name);
});

console.log(array);

Answer 2

你可以像下面这样组合它们

var friends = [{  id: 1122,  name: 'Adrianna Budzinski'}, {  id: 3785,  name: 'Amy Divine'}, {  id: 1555,  name: 'Gale Purdue'}, {  id: 1920,  name: 'Rex Feng'}, {  id: 2010,  name: 'Samella Vizcaino'}, {  id: null,  name: 'Bethanie Weaver'}, {  id: null,  name: 'Celesta Gullo'}, {  id: null,  name: 'Darrick Fort'}, {  id: null,  name: 'Edmundo Boulanger'}, {  id: null,  name: 'Freddie Lanclos'}, {  id: null,  name: 'Gregory Lickteig'}, {  id: null,  name: 'Gwendolyn Cuadra'}, {  id: null,  name: 'Krystal Brosnahan'}, {  id: null,  name: 'Lahoma Pagani'}, {  id: null,  name: 'Senaida Risk'}, {  id: null,  name: 'Valarie Lopes'}];

friends.sort(function(a, b) {
  // check id values are equal even the null
  if (a.id === b.id) {
    // compare the name property in that case
    if (a.name < b.name) return -1;
    if (a.name > b.name) return 1;
    return 0;
  }
  // else check for null
  if (a.id === null) return 1;
  if (b.id === null) return -1;
  // if both are different return the difference to sort based on that
  return a.id - b.id
});

console.log(friends);

---

或者使用String#localeCompare()方法进行简化

var friends = [{  id: 1122,  name: 'Adrianna Budzinski'}, {  id: 3785,  name: 'Amy Divine'}, {  id: 1555,  name: 'Gale Purdue'}, {  id: 1920,  name: 'Rex Feng'}, {  id: 2010,  name: 'Samella Vizcaino'}, {  id: null,  name: 'Bethanie Weaver'}, {  id: null,  name: 'Celesta Gullo'}, {  id: null,  name: 'Darrick Fort'}, {  id: null,  name: 'Edmundo Boulanger'}, {  id: null,  name: 'Freddie Lanclos'}, {  id: null,  name: 'Gregory Lickteig'}, {  id: null,  name: 'Gwendolyn Cuadra'}, {  id: null,  name: 'Krystal Brosnahan'}, {  id: null,  name: 'Lahoma Pagani'}, {  id: null,  name: 'Senaida Risk'}, {  id: null,  name: 'Valarie Lopes'}];

friends.sort(function(a, b) {
  // if id's are equal compare name property
  // id of a is null then return 1
  // id of b is null then return -1
  // else return the difference of them
  return (a.id == b.id && a.name.localeCompare(b.name)) || (a.id === null && 1) || (b.id === null && -1) || (a.id - b.id);
});

console.log(friends);

Answer 3

您可以使用算术计算来确定位置：

逻辑：

• 对于 ID，由于我们只需要查看可用性，请将其设置为 1 或 -1 并进行比较。
• 比较名称并相应排序，然后添加ID比较值。
• 根据优先级设置值。因此，由于需要首先显示所有具有 ID 的成员，因此具有更高的价值。

var data=[{id:1122,name:"Adrianna Budzinski"},{id:3785,name:"Amy Divine"},{id:1555,name:"Gale Purdue"},{id:1920,name:"Rex Feng"},{id:2010,name:"Samella Vizcaino"},{id:null,name:"Bethanie Weaver"},{id:null,name:"Celesta Gullo"},{id:null,name:"Darrick Fort"},{id:null,name:"Edmundo Boulanger"},{id:null,name:"Freddie Lanclos"},{id:null,name:"Gregory Lickteig"},{id:null,name:"Gwendolyn Cuadra"},{id:null,name:"Krystal Brosnahan"},{id:null,name:"Lahoma Pagani"},{id:null,name:"Senaida Risk"},{id:null,name:"Valarie Lopes"}];

data.sort(function(a,b){
  var _id1 = a.id? 1: -1;
  var _id2 = b.id? 1: -1;
  var rank = _id1 >_id2 ? -10: _id1< _id2 ? 10 : 0
  var v = a.name > b.name? 1: a.name < b.name? -1: 0;
  return rank + v;
});

document.getElementById("result").innerHTML = JSON.stringify(data,0,4)

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