不匹配的类型：`expected fn@(&&@type) -> uint` but found `extern fn(@map_a) -> uint`（预期的参数模式 ++ 但找到了 &&）答案

【问题标题】：Mismatched types: `expected fn@(&&@type) -> uint` but found `extern fn(@map_a) -> uint` (expected argument mode ++ but found &&)不匹配的类型：`expected fn@(&&@type) -> uint` but found `extern fn(@map_a) -> uint`（预期的参数模式 ++ 但找到了 &&）
【发布时间】：2012-07-16 20:27:46
【问题描述】：

$ rustc --test mapAsMapKey.rs 
mapAsMapKey.rs:18:43: 18:52 error: mismatched types: expected `fn@(&&@map_a) -> uint` but found `extern fn(@map_a) -> uint` (expected argument mode ++ but found &&)
mapAsMapKey.rs:18     let b: map_b = hashmap::<@map_a, uint>(rmap_hash, rmap_eqer);
                                                             ^~~~~~~~~
mapAsMapKey.rs:18:54: 18:63 error: mismatched types: expected `fn@(&&@map_a, &&@map_a) -> bool` but found `extern fn(@map_a, @map_b) -> bool` (expected argument mode ++ but found &&)
mapAsMapKey.rs:18     let b: map_b = hashmap::<@map_a, uint>(rmap_hash, rmap_eqer);
                                                                        ^~~~~~~~~
error: aborting due to 2 previous errors

防锈功能：

fn rmap_hash (m: @map_a) -> uint { 0 }
fn rmap_eqer (m1: @map_a, m2: @map_b) -> bool { true }

线路触发：

let b: map_b = hashmap::<@map_a, uint>(rmap_hash, rmap_eqer);

【问题讨论】：

标签： types rust

【解决方案1】：

如果你这样写 Rust 函数，它会工作吗？

fn rmap_hash (&&m: @map_a) -> uint { 0 }

fn rmap_eqer (&&m1: @map_a, &&m2: @map_b) -> bool { true }

【讨论】：

是的。正如你在 IRC 上所说。虽然我仍然不确定它们是什么。