在javascript中将两个或多个数组操作为一个数组

Question

我正在从我的服务器获取这组数组：

{ “表名”：[ "广告配置", "api_info", "数据库配置", “对话流”， “雇员”， "ldap_details", "license_details", “登录详细信息”， "maggie_user", "邮件配置", “角色管理”， "server_details", "票务工具", “用例详细信息”， "user_tbl", “人们” ],
“创造”：[ "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:53+05:30", “2021-12-30 10:28:59+05:30” ],
“修改日期”：[ "2021-12-30 12:52:59+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:52+05:30", "2021-12-30 10:42:58+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:53+05:30", “2021-12-30 10:28:59+05:30” ] }

我想实现这个：

[0: {tableName:"adconfig",creation:"2022-01-05 11:28:33+05:30",modifyDate:"2022-01-05 11:28:33+05:30" },

1: {tableName:"api_info",creation:"2022-01-05 11:28:33+05:30",modifyDate:"2022-01-05 11:28:33+05:30"} ,

2: {tableName:"dbconfig",creation:"2022-01-05 11:28:33+05:30",modifyDate:"2022-01-05 11:28:33+05:30"} ,

等等........]

我尝试创建 3 个数组：

tableName: Array(15) 0：“adconfig” 1：“api_info” 2：“dbconfig” 3：“dialog_flow” 4：“employees” 5：“ldap_details” 6：“license_details” 7：“login_details” 8 ：“maggie_user”9：“mailconfig”10：“role_management”11：“server_details”12：“ticketingtool”13：“use_case_details”14：“user_tbl”

创建：数组（15）0：“2022-01-05 11:28:33+05:30”1：“2022-01-05 11:28:33+05:30”2：“2022- 01-05 11:28:33+05:30" 3:"2022-01-05 11:28:33+05:30" 4:"2022-01-05 11:28:33+05:30" 5 : "2022-01-05 11:28:33+05:30" 6: "2022-01-05 11:28:33+05:30" 7: "2022-01-05 11:28:33+05 :30" 8:"2022-01-05 11:28:33+05:30" 9:"2022-01-05 11:28:33+05:30" 10:"2022-01-05 11:28 :33+05:30" 11:"2022-01-05 11:28:34+05:30" 12:"2022-01-05 11:28:34+05:30" 13:"2022-01- 05 11:28:34+05:30" 14:"2022-01-05 11:28:34+05:30"

修改日期：数组（15）0：“2022-01-05 11:28:33+05:30”1：“2022-01-05 11:28:33+05:30”2：“2022 -01-05 11:28:33+05:30" 3:"2022-01-05 11:28:33+05:30" 4:"2022-01-05 11:28:33+05:30" 5：“2022-01-05 11:28:33+05:30”6：“2022-01-05 11:28:33+05:30”7：“2022-01-05 11:28:33+ 05:30" 8:"2022-01-05 11:33:18+05:30" 9:"2022-01-05 11:28:33+05:30" 10:"2022-01-05 11: 33:18+05:30" 11:"2022-01-05 11:28:34+05:30" 12:"2022-01-05 11:28:34+05:30" 13:"2022-01 -05 11:33:19+05:30" 14:"2022-01-05 11:28:34+05:30" 长度：15

然后我尝试加入这三个以获得我想要的但无法获得的东西，如果有人提供任何解决方案，我将非常感激。很抱歉格式问题，因为我在这里很新，所以请原谅我提前谢谢:)

Answer 1

所以一个对象中有3个数组，你想zip它们；每个项目在数组中的索引相同，并且所有三个数组的长度相同。

const zipped = []

for(const i=0; i<response.tableName.length; i++) {
  zipped.push({
    tableName: response.tableName[i],
    creation: response.creation[i],
    modifyDate: response.modifyDate[i],
  })
}

Answer 2

这应该会产生正确的结果。

const serverData = { 
  "tableName": [ "adconfig", "api_info", "dbconfig", "dialog_flow", "employees", "ldap_details", "license_details", "login_details", "maggie_user", "mailconfig", "role_management", "server_details", "ticketingtool", "use_case_details", "user_tbl", "people" ],
  "creation": [ "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:53+05:30", "2021-12-30 10:28:59+05:30" ],
  "modifyDate": [ "2021-12-30 12:52:59+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:52+05:30", "2021-12-30 10:42:58+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:53+05:30", "2021-12-30 10:28:59+05:30" ] 
};

const listLen = serverData["tableName"].length;
const results = [...Array(listLen)].map((_, i) => ({
    tableName: serverData.tableName[i],
    creation: serverData.creation[i],
    modifyDate: serverData.modifyDate[i]
}));

console.log(results);

Answer 3

考虑到每个数组的长度相同并且从服务器接收到“响应”，这里有一个单行解决方案：-

let result = response.tableName.map((name,i) => {
    return {name, response.creation[i], response.modifyDate[i]}
})

Answer 4

在其中一个数组上使用map，并根据索引从其他数组中组合

const data = { 
  "tableName": [ "adconfig", "api_info", "dbconfig", "dialog_flow", "employees", "ldap_details", "license_details", "login_details", "maggie_user", "mailconfig", "role_management", "server_details", "ticketingtool", "use_case_details", "user_tbl", "people" ],
  "creation": [ "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:53+05:30", "2021-12-30 10:28:59+05:30" ],
  "modifyDate": [ "2021-12-30 12:52:59+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:52+05:30", "2021-12-30 10:42:58+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:52+05:30", "2021-12-29 18:11:53+05:30", "2021-12-30 10:28:59+05:30" ] 
};

const { tableName, creation, modifyDate } = data;
const output = tableName.map((tableName, i) => ({
  tableName,
  creation: creation[i],
  modifyDate: modifyDate[i]
}))

console.log(output);