如果您将每个匹配的 KeywordsToProducts 连接到 Keywords,您可以将它们收集起来并进行比较:
var query = from p in Products
join kp in KeywordsToProducts on p.ProductId equals kp.ProductId into kpj
let kws = (from kp in kpj join kw in Keywords on kp.KeywordId equals kw.KeywordId select kw.Keyword)
where words.All(w => kws.Any(kw => kw.Contains(w)))
select p;
但是,我认为如果您先分别执行 KeywordsToProducts 到 Keywords join 会更容易理解(并且可能更有效)(请注意,它显示连接表会更好地命名为 @987654328 @):
var kwToProducts = from kp in KeywordsToProducts
join kw in Keywords on kp.KeywordId equals kw.KeywordId
select new { kp.ProductId, kw.Keyword };
var query = from p in Products
join kwp in kwToProducts on p.ProductId equals kwp.ProductId into kwpj
where words.All(w => kwpj.Any(kwp => kwp.Keyword.Contains(w)))
select p;
虽然我不是(不一定)喜欢提及它,但还要注意 EF 导航属性可以隐藏连接表并使此查询更容易。
应该是这样的:
var query = from p in Products
where words.All(w => p.Keywords.Any(k => k.Contains(w)))
select p;
我假设您打算使用String.Contains,以便用户可以输入部分关键字并仍然找到匹配项。如果你想要求所有的关键字都匹配,这里是相同的代码:
var query = from p in Products
join kp in KeywordsToProducts on p.ProductId equals kp.ProductId into kpj
let kws = (from kp in kpj join kw in Keywords on kp.KeywordId equals kw.KeywordId select kw.Keyword)
where words.All(w => kws.Contains(w))
select p;
拆分子连接:
var kwToProducts = from kp in KeywordsToProducts
join kw in Keywords on kp.KeywordId equals kw.KeywordId
select new { kp.ProductId, kw.Keyword };
var query = from p in Products
join kwp in kwToProducts on p.ProductId equals kwp.ProductId into kwpj
where words.All(w => kwpj.Select(kwp => kwp.Keyword).Contains(w))
select p;
EF 导航属性:
var query = from p in Products
where words.All(w => p.Keywords.Contains(w))
select p;