【发布时间】:2012-03-27 20:58:26
【问题描述】:
所以我在同一个文件中有两个类; ArrayLinkedList 和 ArrayLinkedListRow
在第一个提到的里面我有一个方法
template<class T> friend ostream& operator <<(ostream& s, ArrayLinkedList<T>& ll){
//Extra code for giving s content
return s;
}
还有
template<class T> friend ostream& operator <<(ostream& s, ArrayLinkedListRow<T>& ll){
//Extra code for giving s content
return s;
}
ArrayLinkedListRow 内部。
我收到以下错误
错误 1 错误 C2995: 'std::ostream &operator
它让我发疯,不知道如何解决它。我已经完成了我的研究,但我仍然不知道该怎么做。我坚信这两个类可能与问题有关,尽管错误只是指出了一行。
额外信息: 对于那些对我的简短解释感到困惑的人来说,这是类 ArrayLinkedList 标头。
template<class DT>
class ArrayLinkedList {
private:
DT* _info[MAX_SIZE]; // store data
int _next[MAX_SIZE]; // next node
int _nextEmpty[MAX_SIZE]; //next empty slot
ArrayClass< ArrayLinkedListRow<DT> >* _rows;
int _head; // head of the list
int _firstEmpty; // first empty slot
int _size;
void copy(const ArrayLinkedList<DT>& ll);//copy from another list
// add a new node with next as it's next node and returns the index of new node
int newNode( DT& newObject, int next);
public:
ArrayLinkedList(); // empty and copy constructors
ArrayLinkedList(const ArrayLinkedList<DT>& ll);
//copy constructors linked list object to an existing object. This is a deep copy.
~ArrayLinkedList(); // destructor
ArrayLinkedList(DT& newObject); // Constructor that create a list with newObject as the head
ArrayLinkedList(int capacity); // Constructor with a give capacity
ArrayLinkedList(DT& newObject,int capacity);// Constructor with newObject as the head and capacity
bool isEmpty(); // is the list empty?
int size(); // return the number of nodes stored
void add(DT& newObject); // add an object to the tail
void insertAt(DT& newObject, int position); // insert an object at the position specified
DT remove(); // remove the head
DT removeAt(int position); // remove an object at the position specified
int find(DT key); // find the object that matches key, index of the object
void operator=(const ArrayLinkedList<DT>& ll); // = operator
// overloading [] operator, return a reference to object at the
// Add a new data element to the start of a linked list.
DT& operator[] (const int position); // position in the linked list
// ostream operator
template<class T> friend ostream& operator <<(ostream& s, ArrayLinkedList<T>& ll){
return s;
}
void displayRaw(); // display raw data of the data members
};
【问题讨论】:
-
您能否将问题简化为一个仍然会产生错误的小而完整的示例?
ArrayLinkedList<>和ArrayLinkedListRow<>之间是否存在某种继承关系? -
无继承关系。我将编辑问题,以便您可以看到完整的课程。