需要 PHP 正则表达式专家 - 在字符串中查找文本但使用通配符

Question

我目前有匹配的代码

$data=["as much as I like oranges, I like bananas better",
"there's no rest for the wicked",
"the further I move from my target, the further I get",
"just because I like that song, does not mean I will buy it"];

 if (stripos($data[1], 'just because I') !== false) {
      $line=str_ireplace('just because I','*'.just because I.'*',$data[1]);
      break;
  }

这种方式只匹配包含该文本的任何句子。但我想要它做的是匹配一个通配符，这样它就可以检测一个句型。例如，它可以检测到：

"just because I... (<<any text in between>>) ...does not mean..."

希望这是可以理解的。它还需要匹配文本在句子中出现的位置，并通过在开头和结尾添加 * 来标记它。

Answer 1

您可以使用preg_replace 代替str_ireplace：

$data = ["as much as I like oranges, I like bananas better",
         "there's no rest for the wicked",
         "the further I move from my target, the further I get",
         "just because I like that song, does not mean I will buy it",
         "the further I move from my target, the further I get"];
$pattern = '/(.*)(just because I .* does not mean)(.*)/i';
$replacement = '$1*$2*$3';
foreach ($data as $data_) {
  $line = preg_replace($pattern, $replacement, $data_, -1, $count)."\n";
  if ($count > 0) {
    break;
  }
}
echo $line;

将返回：

*just because I like that song, does not mean* I will buy it

count 变量将包含按照文档进行的替换次数。我添加它是因为看起来你想在第一次替换后跳出循环。