python tkinter接口如何创建一个新的显示txt文件

Question

我构建了一个代码，它接受 python 用户输入并在按下应用时将其插入到文本文件中，如下图所示

当用户插入新文本时文本文件总是会更新，如何在旁边创建一个新按钮以向用户显示最新的文本文件

并希望阻止输入相同的文本 例如，如果文本文件有 (go)，则程序不要再次输入 (go) 这是我的代码

root = Tk()

ivn = StringVar()
inputVarName = Entry(root, textvariable=str(ivn))
ivn.set(str("text1"))
inputVarName.grid(row=0, column=0)

ivn2 = StringVar()
inputVarName2 = Entry(root, textvariable=str(ivn2))
ivn2.set(str("text2"))
inputVarName2.grid(row=1, column=0)




def writetofile():
    content_list = [ivn.get(), ivn2.get()]

    print("\n".join(content_list))    
    with open("help.txt", "a") as f:
        for item in content_list:
            f.write("%s\n" % item)

applyButton = Button(root, text="Apply", command=writetofile)
applyButton.grid(row=2, column=1)



root.mainloop()

Answer 1

为了防止用户插入相同的文本，只需清空这两个条目，您可以在保存到文件之前检查条目是否为空。

您可以使用顶级窗口来显示文件内容。

检查以下示例：

from tkinter import Tk, Toplevel, Button, Entry, StringVar, Text, DISABLED, END, W, E 
import tkinter.ttk as ttk
import tkMessageBox

root = Tk()


ivn = StringVar()
inputVarName = Entry(root, textvariable=str(ivn))
ivn.set(str("text1"))
inputVarName.grid(row=0, column=0,columnspan=2)

ivn2 = StringVar()
inputVarName2 = Entry(root, textvariable=str(ivn2))
ivn2.set(str("text2"))
inputVarName2.grid(row=1, column=0,columnspan=2)


def writetofile():
    content_list = [ivn.get(), ivn2.get()]
    if any(content_list):
        print("\n".join(content_list))

        with open("help.txt", 'r+') as inFile:
            for item in content_list:
                if ("%s\n" % item).encode('UTF-8') in inFile:
                    tkMessageBox.showwarning("Warning", "'%s': Already exists!" % item)
                    return

        with open("help.txt", "a") as f:
            for item in content_list:
                f.write( ("%s\n" % item).encode('UTF-8'))

    ivn.set('')
    ivn2.set('')


def showfile():
    top = Toplevel()
    top.title("help.txt")
    textArea = Text(top)

    scrollbar = ttk.Scrollbar(top, command=textArea.yview)
    scrollbar.grid(row=0, column=1, sticky='nsew')

    textArea['yscrollcommand'] = scrollbar.set

    with open("help.txt", "r") as infile:
        textArea.insert(END, infile.read())

    textArea.grid(row=0, column=0)
    textArea.config(state=DISABLED)

applyButton = Button(root, text="Apply", command=writetofile)
applyButton.grid(row=2, column=0, sticky=W+E)

showButton = Button(root, text="Show", command=showfile)
showButton.grid(row=2, column=1, sticky=W+E)



root.mainloop()

编辑以回答 cmets 中的@IbrahimOzaeri 问题。
您可以使用tkFileDialog.askopenfilename 要求用户选择文件：

from Tkinter import Tk
import Tkinter, Tkconstants, tkFileDialog

root = Tk()
root.filename = tkFileDialog.askopenfilename(initialdir = "/",title = "Select file",filetypes = (("text files","*.txt"),("all files","*.*")))
print (root.filename)

Answer 2

我正在尝试相同的方法，但只有一个输出

import tkinter.ttk as ttk
import tkMessageBox

root = Tk()
root.geometry("500x300")
root.title("The Gatway company")

ivn = StringVar()
inputVarName = Entry(root, textvariable=str(ivn))
ivn.set(str("text1"))
inputVarName.grid(row=0, column=0,columnspan=2)
def writetofile():
    content_list = [ivn.get()]
    if any(content_list):


        with open("help.txt", 'r+') as inFile:
            for item in content_list:
                if ("%s\n" % item).encode('UTF-8') in inFile:
                    tkMessageBox.showwarning("Warning", "'%s': Already exists!" % item)
                    return

        with open("help.txt", "a") as f:
            for item in content_list:
                f.write( ("%s\n" % item).encode('UTF-8'))

    ivn.set('')

def showfile():
    top = Toplevel()
    top.title("help.txt")
    textArea = Text(top)

    scrollbar = ttk.Scrollbar(top, command=textArea.yview)
    scrollbar.grid(row=0, column=1, sticky='nsew')

    textArea['yscrollcommand'] = scrollbar.set

    with open("help.txt", "r") as infile:
        textArea.insert(END, infile.read())

    textArea.grid(row=0, column=0)
    textArea.config(state=DISABLED)

applyButton = Button(root, text="Apply", command=writetofile)
applyButton.grid(row=2, column=0, sticky=W+E)
applyButton.config( height = 5, width = 10 )

showButton = Button(root, text="Show", command=showfile)
showButton.grid(row=2, column=1, sticky=W+E)
showButton.config( height = 5, width = 10 ) 



root.mainloop()

它与您的代码相同，但对于一个条目，我正在考虑以一种用户选择 help.txt 文件的方式编辑它，就像文件请求者一样。