获得与打印相同的结果[重复]答案

【问题标题】：Getting the same result as the print [duplicate]获得与打印相同的结果[重复]
【发布时间】：2020-09-04 11:31:40
【问题描述】：

def dot_trick(username):
    emails = list()
    username_length = len(username)
    combinations = pow(2, username_length - 1)
    padding = "{0:0" + str(username_length - 1) + "b}"
    for i in range(0, combinations):
        bin = padding.format(i)
        full_email = ""

        for j in range(0, username_length - 1):
            full_email += (username[j]);
            if bin[j] == "1":
                full_email += "."
        full_email += (username[j + 1])
        emails.append(full_email + "mars")
    return emails

username = ("marsbros")
print(*dot_trick(username) , sep="\n")

我想得到与print 和sep='\n' 相同的结果，并将其逐行写入文件。

【问题讨论】：

标签： python python-3.x

【解决方案1】：

你可以试试这个

def dot_trick(username):
    emails = list()
    username_length = len(username)
    combinations = pow(2, username_length - 1)
    padding = "{0:0" + str(username_length - 1) + "b}"
    for i in range(0, combinations):
        bin = padding.format(i)
        full_email = ""

        for j in range(0, username_length - 1):
            full_email += (username[j]);
            if bin[j] == "1":
                full_email += "."
        full_email += (username[j + 1])
        emails.append(full_email + "mars")
    return emails

username = ("marsbros")
print(*dot_trick(username) , sep="\n",file=open("username.txt", "a"))
print(*dot_trick(username) , sep="\n")

【讨论】：