Json-c# 和 .net 中的嵌套数组

Question

我正在尝试像这样使用 c# 来创建一个 json 文件

{
  "name" :{
       "firstname": "john",
       "lastname": "Doe" 
   },
   "age":{
       "real": "2",
       "dogyears": "22"
   },
   "boo":{
        "foo":[
           "bar",
           "haa",
           "haha"
         ]
   }
}

我的班级看起来像这样-我不知道这是否正确-

    public class data
    {
        public string[] name { get; set; }
        public string[] age { get; set; }
        public string[] boo {get; set;}
    }

还有什么我需要添加到课程中的吗？

另外，这是我尝试将其写入外部 json 文件的方式

String first_name= firstN.Text;
String last_name=lastN.Text;
....
List<data> dataa = new List<data>();
        dataa.Add(new data()
        {
            //I am not sure what goes here - probably something like this
            firstname = first_name;

        });
        string json = JsonConvert.SerializeObject(dataa.ToArray());

        //write string to file
        System.IO.File.WriteAllText(JsonFilePath, json);

我是新人-所以任何帮助将不胜感激谢谢:)

Answer 1

Panagiotis 评论了非常有用的“将 json 粘贴为类”功能，但我通常更喜欢使用 http://QuickType.io 之类的东西，因为它会生成更多功能完整/有用/符合名称的类集：

// <auto-generated />
//
// To parse this JSON data, add NuGet 'Newtonsoft.Json' then do:
//
//    using Leia;
//
//    var data = Data.FromJson(jsonString);

namespace Leia
{
    using System;
    using System.Collections.Generic;

    using System.Globalization;
    using Newtonsoft.Json;
    using Newtonsoft.Json.Converters;

    public partial class Data
    {
        [JsonProperty("name")]
        public Name Name { get; set; }

        [JsonProperty("age")]
        public Age Age { get; set; }

        [JsonProperty("boo")]
        public Boo Boo { get; set; }
    }

    public partial class Age
    {
        [JsonProperty("real")]
        [JsonConverter(typeof(ParseStringConverter))]
        public long Real { get; set; }

        [JsonProperty("dogyears")]
        [JsonConverter(typeof(ParseStringConverter))]
        public long Dogyears { get; set; }
    }

    public partial class Boo
    {
        [JsonProperty("foo")]
        public string[] Foo { get; set; }
    }

    public partial class Name
    {
        [JsonProperty("firstname")]
        public string Firstname { get; set; }

        [JsonProperty("lastname")]
        public string Lastname { get; set; }
    }

    public partial class Data
    {
        public static Data FromJson(string json) => JsonConvert.DeserializeObject<Data>(json, Agarwal.Converter.Settings);
    }

    public static class Serialize
    {
        public static string ToJson(this Data self) => JsonConvert.SerializeObject(self, Agarwal.Converter.Settings);
    }

    internal static class Converter
    {
        public static readonly JsonSerializerSettings Settings = new JsonSerializerSettings
        {
            MetadataPropertyHandling = MetadataPropertyHandling.Ignore,
            DateParseHandling = DateParseHandling.None,
            Converters =
            {
                new IsoDateTimeConverter { DateTimeStyles = DateTimeStyles.AssumeUniversal }
            },
        };
    }

    internal class ParseStringConverter : JsonConverter
    {
        public override bool CanConvert(Type t) => t == typeof(long) || t == typeof(long?);

        public override object ReadJson(JsonReader reader, Type t, object existingValue, JsonSerializer serializer)
        {
            if (reader.TokenType == JsonToken.Null) return null;
            var value = serializer.Deserialize<string>(reader);
            long l;
            if (Int64.TryParse(value, out l))
            {
                return l;
            }
            throw new Exception("Cannot unmarshal type long");
        }

        public override void WriteJson(JsonWriter writer, object untypedValue, JsonSerializer serializer)
        {
            if (untypedValue == null)
            {
                serializer.Serialize(writer, null);
                return;
            }
            var value = (long)untypedValue;
            serializer.Serialize(writer, value.ToString());
            return;
        }

        public static readonly ParseStringConverter Singleton = new ParseStringConverter();
    }
}

转到http://quicktype.io 并粘贴您的 json，设置您的选项。结束

我与该服务无关。使用“json to c#”之类的网络搜索可以找到很多其他的

---

如何使用它：

C# 看起来很像 JSON：

String first_name= firstN.Text;
String last_name=lastN.Text;

Data d = new Data(){
   Name = new Name(){ FirstName = first_name, LastName = last_name }
};

string json = d.ToJson();
System.IO.File.WriteAllText(JsonFilePath, json);