【发布时间】:2014-06-15 10:51:04
【问题描述】:
您好,我对 php 有点陌生,我正在尝试创建此联系表单。我遇到的一个问题是电子邮件字段被用作接收者电子邮件,而不是 scpianolessons.ie@gmail.com
谁能看到我哪里出错了?
谢谢。
<?php
$Email = Trim(stripslashes($_POST['Email']));
$Name = Trim(stripslashes($_POST['Name']));
$Number = Trim(stripslashes($_POST['Tel']));
$Message = Trim(stripslashes($_POST['Message']));
// validation
$validationOK=true;
if (!$validationOK) {
print "<meta http-equiv=\"refresh\" content=\"0;URL=../php/contactthanks.php\">";
exit;
}
// prepare email body text
$to = "$Email";
$from = "scpianolessons.ie@gmail.com";
$subject = "Piano Lessons";
$Body = "";
$Body .= "Name: ";
$Body .= $Name;
$Body .= "\n";
$Body .= "Number: ";
$Body .= $Number;
$Body .= "\n";
$Body .= "Email: ";
$Body .= $Email;
$Body .= "\n";
$Body .= "Message: ";
$Body .= $Message;
$Body .= "\n";
// send email
$success = mail($to, $Subject, $Body, "From: <$Email>");
// redirect to success page
if ($success){
print "<meta http-equiv=\"refresh\" content=\"0;URL=../php/contactthanks.php\">";
}
else{
print "<meta http-equiv=\"refresh\" content=\"0;URL=error.html\">";
}
?>
【问题讨论】:
-
说实话,你只是从某个地方复制了代码,不知道它在做什么,对吧?在包含
mail()的行中,发件人地址是使用$Email而不是$from定义的,这导致了这种情况的发生。 -
是的,我从 css 技巧中复制了一个表单并尝试更改一些字段。我有一个问题,因为我指出我对这一切都很陌生。
标签: php forms email field contact