使用正则表达式格式化字符串并替换值

Question

我有一组日期时间不正确的行。

是否可以使用 Regex.Replace 更正它们？

    Wed2,8-Jul-21 64 53,0 57 
    Thu2, 9-Jul-21 73 60,0 48
    Fri, 30-Jul-21 86 70,0 36
    Sat,31-Jul-21 84 69,0 38
    Sun0, 1-Aug-21 89 73,0 33
    Mon0,2-Aug-21 98 80,0 24 
    Tue0, 3-Aug-21 91 75,0 31
    Wed0,4-Aug-21 92 75,0 30

    foreach (var row in rows)
    {
        Regex rg = new Regex([pattern]);
        rg.Replace(row, [replacement]);
    }

错误的数据在 dateTime 值中；见下文：

这是不正确的：Wed2,8-Jul-21

正确的值为：Wed,28-Jul-21

另外，这是不正确的：Thu2, 9-Jul-21

正确的值为：Thu,29-Jul-21

Answer 1

如果唯一的问题是转置字符，那么为您的模式执行此操作：

(Mon|Tue|Wed|Thu|Fri|Sat|Sun)(\d), *(\d)

替换为

$1, $2$3

Answer 2

这是一种方法：

var rows = new[]
{
    "Wed2,8-Jul-21 64 53,0 57",
    "Thu2, 9-Jul-21 73 60,0 48",
    "Fri, 30-Jul-21 86 70,0 36",
    "Sat,31-Jul-21 84 69,0 38",
    "Sun0, 1-Aug-21 89 73,0 33",
    "Mon0,2-Aug-21 98 80,0 24",
    "Tue0, 3-Aug-21 91 75,0 31",
    "Wed0,4-Aug-21 92 75,0 30"
};

var rg = new Regex(@"^(\w{3})\d?, ?(\d.*)");

foreach (var row in rows)
{
    var fixedRow = rg.Replace(row, "$1,$2");
    Console.WriteLine(fixedRow);
}

工作示例：https://dotnetfiddle.net/uAMx06

解释：

一般的想法是匹配你感兴趣的部分，将它们与捕获组一起存储，然后从这些组件中重建一个固定的字符串。

^          Matches the beginning of the input.
(          Starts a capture group. Everything that is matched
             between '(' and ')' will be stored and can be
             referenced with $1.
\w{3}      Matches any word character exactly three times.
)          Closes the capture group.
\d?        Matches a digit 0 or 1 times.
,          Matches a literal ','.
 ?         Matches a space character 0 or 1 times.
(          Starts another capture group, referenced with $2.
\d         Matches a single digit.
.*         Matches any string of characters
)          Closes the last capture group.