将类似条目分组python [重复]答案

【问题标题】：group similar entries python [duplicate]将类似条目分组python [重复]
【发布时间】：2013-02-10 20:51:22
【问题描述】：

我有一个 numpy 数组：

array([  2.86656000e+09,   2.86688000e+09,   2.86708000e+09,
     2.86860000e+09,   2.86884000e+09,   2.86908000e+09,
     2.86920000e+09,   2.87024000e+09,   2.87040000e+09,
     2.87056000e+09,   2.87076000e+09,   2.87108000e+09,
     2.87120000e+09,   2.87152000e+09,   2.87260000e+09,
     2.87272000e+09,   2.87280000e+09,   2.87448000e+09,
     2.87464000e+09,   2.87476000e+09,   2.87484000e+09])

对相似值进行分组的最佳方法是什么（例如，差异不大于 1000000）？谢谢解答！！

【问题讨论】：

结果应该是什么样子？您需要一组还是多组？如果有多个，它们可以相交吗？
确实，没看到。正是我正在寻找的东西......

标签： python numpy

【解决方案1】：

作为 cmets 中链接的解决方案的替代方案，应该可以使用以下方法：

In [1]: import numpy as np

In [2]: arr = np.array([  2.86656000e+09,   2.86688000e+09,   2.86708000e+09,
   ...:      2.86860000e+09,   2.86884000e+09,   2.86908000e+09,
   ...:      2.86920000e+09,   2.87024000e+09,   2.87040000e+09,
   ...:      2.87056000e+09,   2.87076000e+09,   2.87108000e+09,
   ...:      2.87120000e+09,   2.87152000e+09,   2.87260000e+09,
   ...:      2.87272000e+09,   2.87280000e+09,   2.87448000e+09,
   ...:      2.87464000e+09,   2.87476000e+09,   2.87484000e+09])

In [3]: np.split(arr, np.where(np.diff(arr) > 1000000)[0] + 1)
Out[3]: 
[array([  2.86656000e+09,   2.86688000e+09,   2.86708000e+09]),
 array([  2.86860000e+09,   2.86884000e+09,   2.86908000e+09,
         2.86920000e+09]),
 array([  2.87024000e+09,   2.87040000e+09,   2.87056000e+09,
         2.87076000e+09,   2.87108000e+09,   2.87120000e+09,
         2.87152000e+09]),
 array([  2.87260000e+09,   2.87272000e+09,   2.87280000e+09]),
 array([  2.87448000e+09,   2.87464000e+09,   2.87476000e+09,
         2.87484000e+09])]

【讨论】：