C - 计算随机数组中元素出现次数的函数

Question

我对整体编程有点陌生，目前正在用 C 编程，我目前正在开发一个程序，该程序首先将 10 个数字随机化，放入一个数组中并将它们打印在屏幕上，然后让用户输入一个整数，然后程序应该检查数组并打印出用户输入的整数在数组中出现了多少次，这就是我遇到问题的地方。

#include <stdio.h>
#include <stdlib.h> 
#include <time.h>

//  Function to initialize random numbers.
int Random()                                                            
{
    srand(time(NULL));                                                  //  To initialize the random number generator.
    return 0;                                                           //  Really only the important part from the function, that it returns something.
}

// Generates randome values for the array.
void setRandomNumber(int inputArray[], int arraySize)                   
{
    int i;
    Random();                                                           //  Calls the "Random" function. 
    for(i = 0; i < arraySize; i++)                                      //  Conditions for when/how many times to run the loop.
        inputArray[i] = (rand() % 10) + 1;                              //  What values the array will get, random numbers between 1 and 10.
}

// Function to count the occurrances of an element.
int countElement(int inputArray[], int arraySize, int elementCount)
{

}

int main(void)
{
    int numbers[10];                                                    
    int loop;
    int run = 1;
    int elementCount = 1;
    setRandomNumber(numbers, 10);                                       //  Calls the "setRandomNumber" fucntion to set random values to the floats in the array. 
    countElement(numbers, 10, elementCount);

    for (loop = 0; loop < 10; loop++)                                   //  Prints out the already randomized values of the array "numbers"
        printf("Number: %d\n", numbers[loop]);

    printf("\nWhat to search for: ");
    scanf_s("%d", &elementCount);                                       //  Takes user input on what number to check.
    printf("The number %d occurs %d times.\n", elementCount, countElement);

    return 0;


}

我们需要使用函数，并且函数头必须看起来像 int countElement(int inputArray[], int arraySize, int elementCount)，在这种情况下，我遇到问题的是 countElement 函数。

Answer 1

很简单

int countElement(int inputArray[], int arraySize, int elementCount)
{
    int count = 0l

    for ( int i = 0; i < arraySize; i++ )
    {
        if ( inputArray[i] == elementCount ) ++count; 
    }

    return count;
}

函数可以这样调用

printf("The number %d occurs %d times.\n", elementCount, 
                                           countElement( numbers, 10, elementCount ) );

虽然这样声明函数会更正确

 size_t countElement( const int inputArray[], size_t arraySize, int elementCount );