【发布时间】:2016-02-29 14:36:18
【问题描述】:
我有一个非常大的表(100 多个字段),我需要在其中比较两条记录。为此,我决定使用 PIVOT。记录将由用户选择(因此它们将是动态的),但现在我将它们作为静态放入。
我的 SQL 如下所示:
-- Where clause params
DECLARE @whereClauseParam VARCHAR(MAX) = '[42] <> [600]' --<-- User will need to determine what the condition will be
--Get the Fields required for the initial pivot
DECLARE @Fields VARCHAR(MAX)= '';
SELECT @Fields+=QUOTENAME(t.name)+', '
FROM sys.columns AS t
WHERE t.object_id = OBJECT_ID('tblSQLAdminInventory')
AND t.name <> 'TransID'
AND t.system_type_id = '60';
--36
--48
--52
--56
--60
--61
--62
--104
--106
--127
--165
--167
--231
--239
-- Get the KeyId's with alias added
DECLARE @keyIDs VARCHAR(MAX)= '';
SELECT @keyIDs+=QUOTENAME(t.TransID)+' AS [KeyID_'+CAST(t.TransID AS VARCHAR(10))+'], '
FROM tblSQLAdminInventory AS t
WHERE TransID IN ('42', '600');
-- Get the KeyId's without alias
DECLARE @keyIDs1 VARCHAR(MAX)= '';
SELECT @keyIDs1+=QUOTENAME(t.TransID)+', '
FROM tblSQLAdminInventory AS t
WHERE TransID IN ('42', '600');
--Generate Dynamic SQL
DECLARE @SQL2 VARCHAR(MAX)= 'SELECT Value AS FieldName, ';
PRINT @SQL2+SUBSTRING(@keyIDs, 1, LEN(@keyIDs)-1)
PRINT @keyIDs
PRINT LEN(@keyIDs)
SELECT @SQL2+=SUBSTRING(@keyIDs, 1, LEN(@keyIDs)-1)+'
FROM
(SELECT TransID , Value , FieldName
FROM
(SELECT TransID,'+SUBSTRING(@Fields, 1, LEN(@Fields)-1)+'
FROM tblSQLAdminInventory) p
UNPIVOT
(FieldName FOR Value IN
('+SUBSTRING(@Fields, 1, LEN(@Fields)-1)+')
)AS unpvt) AS SourceTable
PIVOT
(
MAX(FieldName)
FOR TransID IN ('+SUBSTRING(@keyIDs1, 1, LEN(@keyIDs1)-1)+')
) AS PivotTable
--WHERE '+@whereClauseParam
PRINT(@SQL2);
EXECUTE(@SQL2);
我的 PIVOT 上方的 3 个 PRINT 行打印如下:
SELECT Value AS FieldName, [42] AS [KeyID_42], [600] AS [KeyID_600]
[42] AS [KeyID_42], [600] AS [KeyID_600],
41
一切看起来都很好。但是,我的 PIVOT 上有一个错误:
Msg 537, Level 16, State 5, Line 49
Invalid length parameter passed to the LEFT or SUBSTRING function.
SELECT Value AS FieldName,
Msg 102, Level 15, State 1, Line 1
Incorrect syntax near ','.
谁能告诉我为什么我的 PRINT 语句可以识别所有 3 个字段名称,但我的 PIVOT 语句不能?
奖励问题:当我过滤 t.system_type_id = '56' 时,它会返回数据。对于任何其他 system_type_id,我都会收到错误消息,并且没有返回任何记录。
编辑
根据要求,这是运行时没有错误的 SQL2:
SELECT Value AS FieldName, [42] AS [KeyID_42], [600] AS [KeyID_600]
FROM
(SELECT TransID , Value , FieldName
FROM
(SELECT TransID,[ErisaPlanEndsMM], [ErisaPlanEndsDD], [MLRAvgLivesNumber], [MLRAvgLivesRptYear]
FROM tblSQLAdminInventory) p
UNPIVOT
(FieldName FOR Value IN
([ErisaPlanEndsMM], [ErisaPlanEndsDD], [MLRAvgLivesNumber], [MLRAvgLivesRptYear])
)AS unpvt) AS SourceTable
PIVOT
(
MAX(FieldName)
FOR TransID IN ([42], [600])
) AS PivotTable
--WHERE [42] <> [600]
【问题讨论】:
-
可以添加打印@SQL2的结果吗?
-
我决定尝试通过 system_type_id 将其分开,因为我不断收到字段不是相同数据类型的错误。不确定我的攻击方式是否正确,但这是我能想到的。
标签: sql sql-server substring pivot