查找列表中的任何字符串元素是否包含在字符串列表中

Question

我需要创建一个脚本来根据其中是否存在字符串列表来接受/拒绝某些文本。

我有一个应该用作拒绝机制的关键字列表：

k_out = ['word1', 'word2', 'some larger text']

如果在我下面提供的列表中找到任何这些字符串元素，则该列表应标记为 rejected。这是应该检查的列表：

c_lst = ['This is some text that contains no rejected word', 'This is some larger text which means this list should be rejected']

这就是我所拥有的：

flag_r = False
for text in k_out:
    for lst in c_lst:
        if text in lst:
            flag_r = True

有没有更多的 pythonic 方法来解决这个问题？

Answer 1

您可以使用any 和generator expression：

>>> k_out = ['word1', 'word2', 'some larger text']
>>> c_lst = ['This is some text that contains no rejected word', 'This is some larger text which means this list should be rejected']
>>> any(keyword in string for string in c_lst for keyword in k_out)
True
>>>