Django Authorization - 在函数调用中返回重定向

Question

我正在添加一些自定义授权来验证登录用户是否有权访问我的应用程序的特定部分。它不漂亮，但它有效：

view_permissions = {
    'admin_list': {
        'school':{'userrole':['S','A'], 'usertype':[]},
        'class':{'userrole':['S','A'], 'usertype':[]},
        ' ... '
    },
    'delete_object': { ... },
    'edit_object': { ... },
    }
}

def check_permissions(request, viewname, objecttype):
    if(request.user.userrole in view_permissions[viewname][objecttype]['userrole'] or 
       request.user.usertype in view_permissions[viewname][objecttype]['usertype']
    ):
        return True
    else:
        return False

def delete_object(request, objecttype, objectid):

    # Redirect to home page if not authorized
    if(not check_permissions(request, 'delete_object', objecttype)):
        return redirect('wakemeup:index')

    # Otherwise, continue processing
    myobject.delete()
    ...

    return admin_list(request, objecttype)

我想要做的是将redirect 移动到check_permissions 函数内，如下所示：

def check_permissions(request, viewname, objecttype):
    if( <check permissions are valid> ):
        pass # Authorized: Do nothing and continue with caller view logic
    else:
        return redirect('wakemeup:index') # Unauthorized: redirect to home

def delete_object(request, objecttype, objectid):

    # Redirect to home page if not authorized
    check_permissions(request, 'delete_object', objecttype))

问题在于，check_permissions 函数内的重定向没有任何作用。如果我将return 添加到调用逻辑，它只会重定向：

def delete_object(request, objecttype, objectid):

    # Redirect to home page if not authorized
    return check_permissions(request, 'delete_object', objecttype))

我猜这与嵌套函数调用将其输出一直返回给原始调用者有关。但是有没有一种简单的方法可以让重定向从 check_permissions 函数中工作？

编辑

更新的函数——我必须通过 args[0] 访问 request 对象，但我可以通过 kwargs 访问我的其他变量。我想这是因为在表单中，请求对象只是在幕后传递，而不是作为参数。

def check_perm(view):
    viewname = view.__name__

    def view_wrapper(*args, **kwargs):

        objecttype = kwargs['objecttype']
        myuser = args[0].user

        if not (
            myuser.userrole in view_permissions[viewname][objecttype]['userrole'] or 
            myuser.usertype in view_permissions[viewname][objecttype]['usertype']
        ):
            # Invalid permission - redirect
            return redirect('wakemeup:index')

        # Valid permission - continue
        return view(*args, **kwargs)

    return view_wrapper

...

@check_perm
def delete_object(request, objecttype, objectid):
  ...

Answer 1

我认为函数装饰器是解决这个问题的完美方案。以下允许您检查条件（权限），如有必要，通过重定向劫持响应，如果没有，则继续正常查看响应：

from django.shortcuts import redirect

def check_permissions(view):
    view_name = view.__name__

    def view_wrapper(*args, **kwargs):
        # Check permissions here.
        if False or False or True:
            # Hijack response with a redirect if conditions not met.
            return redirect('wakemeup:index')

        # Conditions met, continue with normal response.
        return view(*args, **kwargs)

    return view_wrapper

@check_permissions
def delete_object(request, object_type, object_id):
    # Your normal view...
    return

另外，请注意它捕获视图名称的方式。在我看来更具活力。