【发布时间】:2018-10-22 23:22:28
【问题描述】:
我正在尝试生成查询。 我需要下表中 TABLEOBJECTID 列中的值,其中 TABLENAME = 'EMPLOYEE' 和 INTERFACE MAINTAINED (CUSTFIELDNAME) = YES (CUSTFIELDVALUE) 和 传输标志 (CUSTFIELDNAME) = YES (CUSTFIELDVALUE) 任何帮助表示赞赏。下面显示的 SQL 不起作用并获取数据,但它也从其他字段获取值。
数据:
TABLEOBJECTID CUSTFIELDID TABLENAME CUSTFIELDNAME CUSFIELDVALUE
2 4 EMPLOYEE INTERFACE MAINTAINED No
2 5 EMPLOYEE TRANSFER HOURS TO AG Yes
2 7 EMPLOYEE TRANSFER FLAG Yes
3 4 EMPLOYEE INTERFACE MAINTAINED Yes
3 7 EMPLOYEE TRANSFER FLAG Yes
31 4 EMPLOYEE INTERFACE MAINTAINED No
31 5 EMPLOYEE TRANSFER HOURS TO AG No
31 6 EMPLOYEE DEFAULT JOB CODE
94 4 EMPLOYEE INTERFACE MAINTAINED No
94 6 EMPLOYEE DEFAULT JOB CODE 0325
94 7 EMPLOYEE TRANSFER FLAG No
96 4 EMPLOYEE INTERFACE MAINTAINED No
96 6 EMPLOYEE DEFAULT JOB CODE 0325
100 4 EMPLOYEE INTERFACE MAINTAINED No
100 5 EMPLOYEE TRANSFER HOURS TO AG No
100 6 EMPLOYEE DEFAULT JOB CODE
100 7 EMPLOYEE TRANSFER FLAG No
101 4 EMPLOYEE INTERFACE MAINTAINED Yes
101 6 EMPLOYEE DEFAULT CODE 9760
101 7 EMPLOYEE TRANSFER FLAG Yes
预期结果:
TABLEOBJECTID CUSTFIELDID TABLENAME CUSTFIELDNAME CUSFIELDVALUE
3 4 EMPLOYEE INTERFACE MAINTAINED Yes
3 7 EMPLOYEE TRANSFER FLAG Yes
101 4 EMPLOYEE INTERFACE MAINTAINED Yes
101 7 EMPLOYEE TRANSFER FLAG Yes
我一直在尝试这个脚本,但它也带来了其他 CUSTFIELDNAME 的结果:
select CWA.TABLEOBJECTID ,CWA.CUSTFIELDID ,CWA.CUSTFIELDNAME ,CWA.CUSTFIELDVALUE ,CWA.TABLENAME ,CWA.TABLEOBJECTID from az.CWCUSTFIELD CWA
inner join az.CWCUSTFIELD CWB on CWA.TABLEOBJECTID =CWB.TABLEOBJECTID and CWA.CUSTFIELDID <> CWB.CUSTFIELDID
where CWA.tablename = 'EMPLOYEE' and CWB.TABLENAME ='EMPLOYEE' and (CWA.CUSTFIELDVALUE = 'YES' and CWB.CUSTFIELDVALUE = 'YES')
【问题讨论】:
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没有足够的信息来回答这个问题。 'TABLEOBJECTID' 是您发布的数据中的重复值,是否存在唯一标识每条记录的列?
标签: sql sql-server database syntax