【发布时间】:2015-09-08 19:25:19
【问题描述】:
我遵循了 techonthenet 上的指南,其中说对于 SUM 查询,您需要将 Sum(expr) 放入 SELECT 语句中,然后将 GROUP BY 放入您选择的所有其他字段(伪代码;如果我错了)。下面是我的尝试。为什么会出现错误
“执行查询时出错。'('附近的语法不正确。错误:102;第9行”
这一切的最终结果将是一份报告,而不仅仅是一个查询。在报告中,除了 [差异] 字段将在底部汇总之外,将显示以下所有字段。我觉得与其在查询中求和,不如在报告中求和……
EDIT - 我删除了 [ALL],但现在我收到错误消息“不能在用于 GROUP BY 子句的分组列表的表达式中使用聚合或子查询。”它还说这个错误在第29行。我会在下面标记它。
SELECT
JOB.WHSE,
LEFT(RESSCHD000.RESID, 6) AS Line,
RIGHT(LEFT(JOB000.JSID, 11), 10)+ '-' +RIGHT(LEFT(JOB000.JSID, 27), 2) AS [Job Number],
LEFT(RESSCHD000.STARTDATE, 7)+ ' ' +RIGHT(Convert(Datetime, MIN(RESSCHD000.STARTDATE)), 8) AS [Start],
LEFT(RESSCHD000.ENDDATE, 7)+ ' ' +RIGHT(Convert(Datetime, MAX(RESSCHD000.ENDDATE)),8) AS [End],
RESSCHD000.STATUSCD,
Sum((Dateadd("n",DateDiff("n", MIN(RESSCHD000.STARTDATE),MAX(RESSCHD000.ENDDATE)),'00:00:00'))) AS [SumOfDifference],
RESSCHD000.JOBTAG,
CASE
WHEN Dateadd("n",DateDiff("n", MIN(RESSCHD000.STARTDATE),MAX(RESSCHD000.ENDDATE)),'00:00:00') > '3:59:00'
THEN 'Full Sanitation'
ELSE 'Dry Clean'
END AS [Type of Sanitation],
jrt_sch.Uf_Quoted_Crew_Size AS [Crew Size]
FROM
RESSCHD000 INNER JOIN JOB000 ON RESSCHD000.JOBTAG = JOB000.JOBTAG
INNER JOIN JOB ON JOB.JOB = RIGHT(LEFT(JOB000.JSID, 11), 10) AND JOB.suffix = RIGHT(LEFT(JOB000.JSID, 27), 2)
LEFT OUTER JOIN jrt_sch ON jrt_sch.job = job.job
WHERE
job.job_date = @job_date
GROUP BY
JOB.WHSE,
LEFT(RESSCHD000.RESID, 6),
RIGHT(LEFT(JOB000.JSID, 11), 10)+ '-' +RIGHT(LEFT(JOB000.JSID, 27), 2), --line 29
LEFT(RESSCHD000.STARTDATE, 7)+ ' ' +RIGHT(Convert(Datetime, MIN(RESSCHD000.STARTDATE)), 8),
LEFT(RESSCHD000.ENDDATE, 7)+ ' ' +RIGHT(Convert(Datetime, MAX(RESSCHD000.ENDDATE)),8),
RESSCHD000.STATUSCD,
RESSCHD000.JOBTAG,
CASE
WHEN Dateadd("n",DateDiff("n", MIN(RESSCHD000.STARTDATE),MAX(RESSCHD000.ENDDATE)),'00:00:00') > '3:59:00'
THEN 'Full Sanitation'
ELSE 'Dry Clean'
END,
jrt_sch.Uf_Quoted_Crew_Size
HAVING
RESSCHD000.STATUSCD='s'
【问题讨论】:
-
你想得到什么?
Sum([All] DateAdd())真的没有意义 -
首先你可以让这堵文字墙变得可读
标签: sql reporting-services syntax