【发布时间】:2014-05-23 15:42:41
【问题描述】:
$one=$_POST['one'];
$two=$_POST['two'];
$three=$_POST['three'];
$four=$_POST['four'];
$five=$_POST['five'];
$six=$_POST['six'];
$seven=$_POST['seven'];
$eight=$_POST['eight'];
$nine=$_POST['nine'];
$ten=$_POST['ten'];
if ( $one == "gift" or $two == "gift" or $three == "gift" or $four == "gift" or $five == "gift" or $six == "gift" or $seven == "gift" or $eight == "gift" or $nine == "gift" or $ten == "gift" ) {
echo "<meta http-equiv='refresh' content='0; url=./gift.php?item=" . ??? . "' />";
}
我在里面放什么???填写触发 if 语句的变量名...
【问题讨论】:
-
使用数组而不是十个变量。
-
有趣的事实:OP 已经有一个不错的数组 :)
-
^ 实际上是一个超级数组...
-
这很落后...为什么不使用 $_POST['GIFT'] = one->ten ?!?!
-
大声笑,但你知道像数组一样访问它吗?!
标签: php if-statement syntax syntax-error