【发布时间】:2021-12-30 14:32:31
【问题描述】:
您好,我正在尝试制作一个在线参考生成器,当用户单击我的 html 中的三个按钮之一时,将出现一个弹出表单。我遇到的问题是我想一次将其限制为一个表单,因此如果用户单击另一个按钮,则会出现一个警报,告诉他们关闭现有表单。
这是我显示三个按钮的 html。
<div class="front-page">
<div class="grid-container">
<h1>What would you like to reference?</h1>
<button type="button1" class="button1" onclick="openForm()">
<span class="button__text">Book</span>
<span class="button__icon"></span>
<i class="fas fa-book"></i>
</button>
<button type="button1" class="button1" onclick="openFormW()">
<span class="button__text">Website</span>
<span class="button__icon"></span>
<i class="fas fa-laptop"></i>
</button>
<button type="button1" class="button1" onclick="openFormA()">
<span class="button__text">Article</span>
<span class="button__icon"></span>
<i class="far fa-file-alt"></i>
</button>
</div>
</div>
这是我试图在每个函数中调用 if 语句的 javascript 代码。
function openForm() {
if(openFormA || openFormW != null) {
alert("unable to open two forms at once, Please close existing form")
} else {
document.getElementById("bookForm").style.display = "block";
}
}
function closeForm() {
document.getElementById("bookForm").style.display = "none";
}
function openFormW() {
document.getElementById("websiteForm").style.display = "block";
}
function closeFormW() {
document.getElementById("websiteForm").style.display = "none";
}
function openFormA() {
document.getElementById("articleForm").style.display = "block";
}
function closeFormA() {
document.getElementById("articleForm").style.display = "none";
}
块引用
【问题讨论】:
标签: javascript html forms web