【发布时间】：2017-03-25 15:03:58
【问题描述】：
我有一个包含章节的表格，每个章节前面都有一个按钮。
现在我想在单击删除按钮时删除一行，并且我想触发删除查询以从数据库中删除该行。
我尝试了 2 3 种方法从表中删除一行，但它没有被删除。
<!doctype html>
<html>
<head>
<title>Chapters</title>
</head>
<body>
<style>
td {
text-align: left;
}
</style>
<script>
var par = $(this).parent().parent(); //tr
par.remove();
</script>
<table id="example" style="width:50%">
<tr>
<th><font size="5">Chapters</font></th>
</tr>
<?php
$dbh = new PDO('mysql:host=174.13.54;dbname=handbook', 'airman', 'airman');
$stmt = $dbh->prepare("SELECT * FROM chapters");
$stmt->execute();
$results = $stmt->fetchall(PDO::FETCH_ASSOC);
if(count($results) > 0)
{
foreach($results as $chapter)
{
if($chapter['type'] == 1)
{
$type = "SSgt";
}
elseif($chapter['type'] == 2)
{
$type = "TSgt";
}
elseif($chapter['type'] == 3)
{
$type = "MSgt";
}
?>
<tr>
<td><?php $chapter['id']; echo $chapter['title'];echo " " . "(" .$type.")";?></td>
<td><input type="button" value="Delete"></td>
</tr>
<?Php
}
?>
</table>
</body>
</html>
<?php
}
?>
我该怎么做？有人可以帮忙吗？
编辑：
chapterDelete.php
<!doctype html>
<html>
<head>
<title>Chapters</title>
</head>
<form method="post" action="deleteChapter.php" enctype="multipart/form-data">
<body>
<style>
td {
text-align: left;
}
</style>
<table id="example" style="width:50%">
<tr>
<th><font size="5">Chapters</font></th>
</tr>
<?php
$dbh = new PDO('mysql:host="138.75.54;dbname=handbook', 'airman', 'airman12345');
$stmt = $dbh->prepare("SELECT * FROM chapters");
$stmt->execute();
$results = $stmt->fetchall(PDO::FETCH_ASSOC);
if(count($results) > 0)
{
foreach($results as $chapter)
{
if($chapter['type'] == 1)
{
$type = "SSgt";
}
elseif($chapter['type'] == 2)
{
$type = "TSgt";
}
elseif($chapter['type'] == 3)
{
$type = "MSgt";
}
?>
<tr>
<td><?php echo $chapter['title'];echo " " . "(" .$type.")";?></td>
<td><input type="button" class="removeRowButton" id = "<?php $chapter['id']?>" value="Delete"></td>
</tr>
<?Php
}
?>
</table>
</body>
</form>
</html>
<script
$('.removeRowButton').click(function(){
var rowID= $(this).attr('id');
$.get( "deleteChapter.php?rowID=" + rowID, function( error ) {
if(error == 0){
$('tr#' + rowID).remove();
}
else{
alert('MySQL error!');
}
});
});
</script>
<?php
}
?>
删除章节.php
<?php
ini_set('display_errors', 1);
error_reporting(1);
ini_set('error_reporting', E_ALL);
$dbh = new PDO('mysql:host=138.75.54;dbname=handbook', 'airman', 'airman12345');
$stmt = $dbh->prepare("DELETE FROM `chapters` WHERE `rowID`= '" . $_GET["rowID"]);
$stmt->execute();
$result = $stmt->fetch(PDO::FETCH_ASSOC);
if(count($result) > 0)
{
echo 'row deleted';
}
else{
echo 'row could not delete';
}
?>
点击删除按钮没有任何反应。
编辑 2：
<!doctype html>
<html>
<head>
<title>Chapters</title>
</head>
<form method="post" action="chapterDelete.php" enctype="multipart/form-data">
<body>
<style>
td {
text-align: left;
}
</style>
<table id="example" style="width:50%">
<tr>
<th><font size="5">Chapters</font></th>
</tr>
<?php
ini_set('display_errors', 1);
error_reporting(1);
ini_set('error_reporting', E_ALL);
$dbh = new PDO('mysql:host=1775.54;dbname=handbook', 'airman', 'airman');
$stmt = $dbh->prepare("SELECT * FROM chapters");
$stmt->execute();
$results = $stmt->fetchall(PDO::FETCH_ASSOC);
if(count($results) > 0)
{
foreach($results as $chapter)
{
if($chapter['type'] == 1)
{
$type = "SSgt";
}
elseif($chapter['type'] == 2)
{
$type = "TSgt";
}
elseif($chapter['type'] == 3)
{
$type = "MSgt";
}
?>
<tr>
<td><?php echo $chapter['title'];echo " " . "(" .$type.")";?></td>
<td><input type="button" onClick= "this.form.submit()" value="Delete<?php $chapter['id']?>"</input></td>
</tr>
<?Php
}
?>
</table>
</body>
</form>
</html>
<?php
}
function delete($id)
{
$dbh = new PDO('mysql:host=174.138.75.54;dbname=airman_handbook', 'airman', 'airman12345');
$stmt = $dbh->prepare("DELETE FROM `chapters` WHERE `id`= " . $id);
$stmt->execute();
$result = $stmt->fetch(PDO::FETCH_ASSOC);
if(count($result) > 0)
{
echo 'row deleted';
}
else{
echo 'row could not delete';
}
}
?>
我可以在不使用 ajax 的情况下这样做吗？但它不起作用。
【问题讨论】：
-
从表名中删除其中 id = $tbl_id
-
我知道我需要知道如何在 html 或 java 脚本中实现它的查询？@Chris
-
您似乎还没有创建表单，只是一个输入，因此您需要对其进行排序以提交或使用 javascript 来监听点击收集所需的信息并向服务器提交 ajax 调用运行 php 代码。
-
Google jquery ajax，试试看，如果你有问题再回来 - 请不要让别人为你写完整的解决方案
-
你不用html或javascript实现，你用php实现，然后用html或javascript触发。