如何使用 mysql 使用 php 中的按钮删除行答案

【问题标题】：How to delete a row using a button in php using mysql如何使用 mysql 使用 php 中的按钮删除行
【发布时间】：2019-02-20 03:50:08
【问题描述】：

我在从表中删除行时遇到问题。当我单击“删除”按钮时，它确实将我带到了下一页，并显示“从播放器中删除了 0 行”。基本上，它执行正确，但我无法删除选定的行。我已经能够显示并添加到表格中。

Player.php

<table id="table table-bordered">
<tr>
    <th>Id#</th>
    <th>Player(s)</th>
    <th>Position</th>
</tr>

if(!($stmt = $mysqli->prepare("SELECT id_Player, name_Player, position_Player FROM player s ORDER BY position_Player ASC"))){
echo "Prepare failed: "  . $mysqli->connect_errno . " " . $mysqli->connect_error;
}

if(!$stmt->execute())
{
echo "Execute failed: "  . $mysqli->connect_errno . " " . $mysqli->connect_error;
}
if(!$stmt->bind_result($id_Player, $name_Player, $position_Player))
{
 echo "Bind failed: "  . $mysqli->connect_errno . " " . $mysqli->connect_error;   
}

    while($stmt->fetch()){
    echo "<tr><td>  $id_Player </td> <td>  $name_Player </td><td>  $position_Player  </td>";

    ?>
        <td>
            <form id="delete" method="post" action="deletePlayers.php">

                <input type="submit" name="id_Player" value="Delete!"/>    

            </form>
        </td>
    </tr>

deletePlayers.php

if(!($stmt = $mysqli->prepare("DELETE FROM player WHERE id_Player  = ?"))){
    echo "Prepare failed: "  . $stmt->errno . " " . $stmt->error;}
if(!($stmt->bind_param("s",$_POST['id_Player']))){
    echo "Bind failed: "  . $stmt->errno . " " . $stmt->error;}
if(!$stmt->execute()){
    echo "Execute failed: "  . $stmt->errno . " " . $stmt->error;}     
else {
    echo "Removed " . $stmt->affected_rows . " row from player. <br/><br/><strong> Returning to 'Add Players'</strong>";}

【问题讨论】：

作为一种干净的方法，请使用 一个表单 包含整个表格，多个提交按钮具有相同的name="delete" 和不同的value="<?php echo "$id_Player"; ?>" 只有实际按下的按钮才会只要它确实具有name 属性，就与表单一起提交。这样，您甚至可以使用复选框并一次删除多条记录。

标签： php mysql sql post button

【解决方案1】：

问题出在这行代码，

if(!($stmt->bind_param("s",$_POST['id_Player']))){}

这里$POST['id_player'] 的值是Delete!，因为您在HTML 代码中传递输入类型提交的名称，我认为您的数据库中没有任何等于Delete! 的ID。

解决方案

你需要做的是你需要使用一个隐藏的输入，它将像这样保存id_Player 值，

if(!($stmt = $mysqli->prepare("SELECT id_Player, name_Player, position_Player FROM player s ORDER BY position_Player ASC"))){
echo "Prepare failed: "  . $mysqli->connect_errno . " " . $mysqli->connect_error;
}

if(!$stmt->execute())
{
echo "Execute failed: "  . $mysqli->connect_errno . " " . $mysqli->connect_error;
}
if(!$stmt->bind_result($id_Player, $name_Player, $position_Player))
{
 echo "Bind failed: "  . $mysqli->connect_errno . " " . $mysqli->connect_error;   
}

    while($stmt->fetch()){
    echo "<tr><td>  $id_Player </td> <td>  $name_Player </td><td>  $position_Player  </td>";

    ?>
        <td>
            <form id="delete" method="post" action="deletePlayers.php">
                <input type="hidden" name="id_Player" value="<?= $id_Player ?>"/>
                <input type="submit" value="Delete!"/>    

            </form>
        </td>
    </tr>

【讨论】：