如何仅在按下所有按钮时才启用按钮？

Question

假设我在一个应用中有六个按钮，并且我只想在所有六个按钮都被点击的情况下启用第七个按钮。如何在 Xcode 9 中实现这一点？

Answer 1

这可以作为你的起点。

(1)。创建以下数组：

//1. Create An Array To Store The Buttons
var buttonArray = [UIButton]()

//2. Create An Array Of Bools So We Can Determine Which Buttons Have Been Pressed
var buttonCheckArray = [false, false, false, false, false, false]

(2)。生成按钮：

 /// Creates 7 Buttons & Adds Them To The Screen
func createButtons(){

    for index in 0 ..< 7{

        //1. Create The Button
        let button = UIButton(frame: CGRect(x: (index * 100) + index * 10, y: 200 , width: 100, height: 100))
        button.setTitle("\(index)", for: .normal)
        button.backgroundColor = .green
        button.tag = index
        button.addTarget(self, action: #selector(buttonPressed(_:)), for: .touchUpInside)
        print(index)

        //2. Add The Button To The Button Array
        buttonArray.append(button)

        //3. Disable The Final Button
        if button.tag == 6 {
            button.isUserInteractionEnabled = false
        }

        //4. Add The Button To The View
        self.view.addSubview(button)
    }

}

(3)。创建验证函数：

/// Determines Which Button Has Been Pressed & Adjusts The buttonCheckArray
///
/// - Parameter sender: UIButton
@IBAction func buttonPressed(_ sender: UIButton){

    //1. Get The Button Tag
    let buttonPressedIndex = sender.tag

    //2. Change The Background Colour
    sender.backgroundColor = .purple

    //3. Change The Bool Value In The Array For The Six Buttons
    if sender.tag != 6{
        buttonCheckArray[buttonPressedIndex] = true
    }


    if buttonCheckArray.contains(false){
        print("Not All 6 Buttons Have Been Selected")
    }else{
        print("All 6 Buttons Have Been Selected")

        guard let finalButton = buttonArray.last else { return }
        finalButton.isUserInteractionEnabled = true

    }

}