【发布时间】:2017-06-14 09:14:23
【问题描述】:
我有从主线程调用的方法。此方法正在创建一个新线程。代码如下所示:
MouseCursorWallObject MouseCursorWall = null;
List<MovingRectangle> MovingRectangles = null;
DrawingImage RenderedImage;
public MainWindow()
{
InitializeComponent();
PrepareObjects();
GameLoopRun();
}
private void GameLoopRun()
{
Thread thread = new Thread(() =>
{
while (true)
{
DateTime dtStart = DateTime.Now;
Events();
Update();
Display();
DateTime dtEnd = DateTime.Now;
TimeSpan ts = dtEnd - dtStart;
if (SkipTicks - ts.TotalMilliseconds >= 0)
{
Thread.Sleep((int)(SkipTicks - ts.TotalMilliseconds));
}
}
});
thread.Start();
}
在 Display() 方法中,我正在尝试更新图像控件。 “Display()”方法如下所示:
private void Display()
{
DrawingGroup imageDrawings = new DrawingGroup();
// Drawing main canvas
imageDrawings.Children.Add(DrawingObject(500, 350, 0, 0, new Uri(@"Images\gameCanvas.jpg", UriKind.Relative)));
// Drawing mouse cursor wall
imageDrawings.Children.Add(DrawingObject(MouseCursorWall.Width, MouseCursorWall.Height, MouseCursorWall.GetLocX, MouseCursorWall.GetLocY, MouseCursorWall.DisplayTexture));
for (int i = 0; i < MovingRectangles.Count; i++)
{
MovingRectangle o = MovingRectangles[i];
// Drawing moving object
imageDrawings.Children.Add(DrawingObject(20, 20, o.GetLocX, o.GetLocY, o.TextureUri));
}
if (GamePause == true)
{
}
RenderedImage = new DrawingImage(imageDrawings);
// Image control on main UI thread
renderImage.Dispatcher.Invoke(() =>
{
renderImage.Source = RenderedImage;
});
}
问题是当我尝试使用 Dispatcher.Invoke 更新图像控件时,我收到错误“调用线程无法访问此对象,因为不同的线程拥有它”。我尝试了很多不同的选项,但只有一个可以正常工作:
private void Display()
{
this.Dispatcher.Invoke(() => {
DrawingGroup imageDrawings = new DrawingGroup();
// Drawing main canvas
imageDrawings.Children.Add(DrawingObject(500, 350, 0, 0, new Uri(@"Images\gameCanvas.jpg", UriKind.Relative)));
// Drawing mouse cursor wall
imageDrawings.Children.Add(DrawingObject(MouseCursorWall.Width, MouseCursorWall.Height, MouseCursorWall.GetLocX, MouseCursorWall.GetLocY, MouseCursorWall.DisplayTexture));
for (int i = 0; i < MovingRectangles.Count; i++)
{
MovingRectangle o = MovingRectangles[i];
// Drawing moving object
imageDrawings.Children.Add(DrawingObject(20, 20, o.GetLocX, o.GetLocY, o.TextureUri));
}
if (GamePause == true)
{
}
RenderedImage = new DrawingImage(imageDrawings);
renderImage.Source = RenderedImage;
});
}
你能解释一下为什么“Display()”方法的第二个选项可以正常工作,但第一个选项会抛出异常吗?我做错了什么?
【问题讨论】:
-
我已经找到那个话题了。
-
好的,如果您首先 .Freeze() DrawingImage,您可能能够让第一个示例工作,但您可能应该在 UI 线程上创建它(根据您的第二个示例)。
标签: c# wpf multithreading invoke dispatcher