django 1.11.x 升级到 2.0 中的 urls 错误

Question

我正在将我的项目从 django 1.11.x 迁移到 2.0。在我找到网址之前，我一切都进展顺利。我碰巧有这样的导入

from cashondelivery.dashboard.app import application as cod_app

我的 url 模式为

url(r'^dashboard/cod/', include(cod_app.urls)),

但我的终端出现以下错误

url(r'^dashboard/cod/', include(cod_app.urls)),
  File ".../dev/lib/python3.6/site-packages/django/urls/conf.py", line 27, in include
    'provide the namespace argument to include() instead.' % len(arg)
django.core.exceptions.ImproperlyConfigured: Passing a 3-tuple to include() is not supported. Pass a 2-tuple containing the list of patterns and app_name, and provide the namespace argument to include() instead.

我真的很感激修复。

现金交付->仪表板->应用程序

import django
from django.conf.urls import url
from django.contrib.admin.views.decorators import staff_member_required

from oscar.core.application import Application

from . import views


class CashOnDeliveryDashboardApplication(Application):
    name = None
    default_permissions = ['is_staff', ]

    list_view = views.TransactionListView
    detail_view = views.TransactionDetailView

    def get_urls(self):
        urlpatterns = [
            url(r'^transactions/$', self.list_view.as_view(),
                name='cashondelivery-transaction-list'),
            url(r'^transactions/(?P<pk>\d+)/$', self.detail_view.as_view(),
                name='cashondelivery-transaction-detail'),
        ]

        if django.VERSION[:2] < (1, 8):
            from django.conf.urls import patterns

            urlpatterns = patterns('', *urlpatterns)

        return self.post_process_urls(urlpatterns)


application = CashOnDeliveryDashboardApplication() 

Answer 1

您需要删除include() 并直接传递urls：

url(r'^dashboard/cod/', cod_app.urls),

在 Django 2 中删除了 urls 属性 returns a 3-tuple，而不是 urlpatterns 的列表，并且支持将其传递给 include()。

Answer 2

在django2 中，其path 用于普通网址，re_path 用于使用正则表达式的网址。

path('dashboard/cod/', include(cod_app.urls)),