【发布时间】:2014-04-23 10:27:52
【问题描述】:
您好,我想将此 cmd curl 转换为 JQuery Ajax Post:
curl -k -X POST https://openshift.redhat.com/broker/rest/domains/MyDomain/applications
--user "user@myemail.com:password"
--data "name=myapp&cartridge=php-5.3&scale=true"
这就是我所做的:
jQuery.ajax({
url: 'https://openshift.redhat.com/broker/rest/domains/MyDomain/applications ',
username: 'user@myemail.com',
password: 'password',
type: 'POST',
dataType: 'json',
contentType: 'application/json',
processData: false,
data: 'name=myapp&cartridge=php-5.3&scale=true"',
success: function (data) {
alert(JSON.stringify(data));
},
error: function(xhr, status, error) {
alert("(" + xhr.responseText + ")");
}
});
我在我的警报中提交后收到此错误:
(<!DOCTYPE HTML PUBLIC "-//IETF//DTD HTML 2.0//EN">
<html><head>
<title>404 Not Found</title>
</head><body>
<h1>Not Found</h1>
<p>The requested URL /https://openshift.redhat.com/broker/rest/domains/MyDomain/applications was not found on this server.</p>
<hr>
<address>Apache/2.4.6 (Fedora) Server at drupal-pcsol.openshift.local Port 80</address>
</body></html>
)
有什么想法吗?
【问题讨论】:
-
in
error: function(xhr, status, error) {你能提醒xhr.responseText的值吗? -
它为空,
xhr.responseText中没有任何内容 -
是的,这就是问题所在。
eval("()");会给你语法错误。 -
谢谢,删除
eval删除了syntaxe error但我仍然有xhr.responseText为空,任何想法 -
data: 'name=myapp&cartridge=php-5.3&scale=true"',不是contentType: 'application/json',
标签: javascript php jquery ajax curl