将第 3 方表数据拉入数组/json

Question

我正在尝试使用 PHP 将此外部表数据转换为数组/JSON。我能够使用 XPath 并计算 td 等来做到这一点，但是，数据每周都会发生一些变化并且把所有事情都搞砸了......有没有一种好的方法来提取这些信息并使用条件语句来根据玩家的显示适当的值姓名？这是表格的链接See Here

我想得到类似的东西

Player name:
    GAMES:   
    MPR:
    PPR:
Player name:
    GAMES:   
    MPR:
    PPR:
etc...

如果有人能帮助我或指出正确的方向，我将不胜感激！这让我发疯了，如果有必要我什至会付钱。

谢谢！

这是我当前的代码

$urll = 'http://www.leagueleader.net/sharedreport.php?operatorid=98&code=1928e435-8dbe-450f-8bca-74f603f892f0';

$options = array (
    CURLOPT_RETURNTRANSFER => true,     // return web page
    CURLOPT_HEADER         => false,    // don't return headers
    CURLOPT_FOLLOWLOCATION => true,     // follow redirects
    CURLOPT_ENCODING       => "",       // handle all encodings
    CURLOPT_USERAGENT      => "Mozilla/5.0 (Windows NT 6.1; WOW64; rv:18.0) Gecko/20100101 Firefox/18.0", // something like Firefox 
    CURLOPT_AUTOREFERER    => true,     // set referer on redirect
    CURLOPT_CONNECTTIMEOUT => 120,      // timeout on connect
    CURLOPT_TIMEOUT        => 120,      // timeout on response
    CURLOPT_MAXREDIRS      => 10,       // stop after 10 redirects
);

$curl = curl_init($urll);
curl_setopt_array( $curl, $options );
$content = curl_exec($curl);
curl_close($curl);
$dom = new DOMDocument();
@$dom->loadHTML($content);
$xpath = new DOMXPath($dom); 

$tabless = $dom->getElementsByTagName('tbody'); 
$rows = $tabless->item(0)->getElementsByTagName('tr');

foreach ($rows as $roww) 
{ 

$colss = $roww->getElementsByTagName('td');

//$player = $cols->item(0)->nodeValue; $pstats[$i]['player'] = trim($player);
//$percentage = $cols->item(1)->nodeValue; $pstats[$i]['gamesplayed'] = trim($percentage);
$cricket = $colss->item(2)->nodeValue; $pstats[$j]['cricket'] = trim($cricket);
$o1 = $colss->item(3)->nodeValue; $pstats[$j]['01'] = trim($o1);


$j++;
} 

Answer 1

您并不是在说 DOM 中发生了什么变化，因此很难制定“始终有效”的解决方案。

这是一个分两个阶段解析结果的解决方案。第一阶段从表中获取数据，然后第二阶段至少需要 4 个元素，否则继续。如果再次更改，应该很容易调试。

<?php
$doc = new DOMDocument();
$doc->loadHTML(file_get_contents('...'));
$doc->strictErrorChecking = false;

$pre = [];
foreach ($doc->getElementsByTagName('table') as $table) {
    foreach ($table->getElementsByTagName('tr') as $i => $tr) {
        $y = 0;
        foreach ($tr->childNodes as $td) {
            $text = trim($td->nodeValue);

            if ($y > 7) {
                unset($pre[$i]);
                continue;
            }

            if (empty($text)) {
                continue;
            }

            $pre[$i][] = $text;
            $y++;
        }
    }
}

// normalise
$result = [];
foreach ($pre as $row) {
    if (count($row) != 4 || $row[0] == 'Team Totals:') {
        continue;
    }

    if (!is_numeric($row[1]) || !is_numeric($row[2]) || !is_numeric($row[3])) {
        // looks broke again, send email to developer ;p
        continue;
    }

    $result[$row[0]] = [
        'name' => $row[0],
        'games' => $row[1],
        'mpr' => $row[2],
        'ppd' => $row[3]
    ];
}

echo '<pre>'.print_r($result, true).'</pre>';

/*
Array
(
    ['Lawrence Cherone'] => Array
        (
            [name] => Lawrence Cherone
            [games] => 51
            [mpr] => 5.00
            [ppd] => 67.48
        )

    ['Scott Sandberg'] => Array
        (
            [name] => Scott Sandberg
            [games] => 51
            [mpr] => 4.02
            [ppd] => 33.18
        )

*/
?>

根据结果构建表格：

<table>
    <thead>
        <tr>
            <?php foreach (array_values($result)[0] as $key => $row): ?>
            <th><?= ucfirst($key) ?></th>
            <?php endforeach ?>
        </tr>
    </thead>
    <tbody>
        <?php foreach ($result as $key => $row): ?>
        <tr>
            <?php foreach ($row as $row): ?>
            <td><?= $row ?></td>
            <?php endforeach ?>
        </tr>
        <?php endforeach ?>
    </tbody>
</table>

或访问个别球员的统计数据：

<?= $result['Scott Sandberg']['games'] ?>

希望对你有帮助。