谷歌云函数（获取图片尺寸）

Question

我正在尝试使用云函数验证我的 Firebase 存储中帖子的图像尺寸。我想做的是：

1：让用户上传图片

2：上传后，后端检查尺寸

2.1：如果它具有良好的尺寸，请不要删除它

2.2：否则，将其从存储中删除

代码如下：

// Validate image dimensions
exports.validateImageDimensions = functions
  .region("us-central1")
  .runWith({ memory: "1GB", timeoutSeconds: 120 })
  .storage.object()
  .onFinalize(async (object) => {
    // Get the bucket which contains the image
    const bucket = gcs.bucket(object.bucket);

    // Get the name
    const filePath = object.name;

    // Check if the file is an image
    const isImage = object.contentType.startsWith("image/");

    // Check if the image has valid dimensions
    const hasValidDimensions = true; // TODO: How to get the image dimension?

    // Do nothing if is an image and has valid dimensions
    if (isImage && hasValidDimensions) {
      return;
    }

    try {
      await bucket.file(filePath).delete();

      console.log(
        `The image ${filePath} has been deleted because it has invalid dimensions.`
      );

      // TODO - Remove image's document in firestore
    } catch (err) {
      console.log(`Error deleting invalid file ${filePath}: ${err}`);
    }
});

但我不知道如何获取对象尺寸。我检查了文档但没有答案。

有什么想法吗？

Answer 1

使用 sharp ，这里是 documentation 谈论它：

const metadata = await sharp('image.jpg').metadata();

const width = metadata.width;
const height = metadata.height;

functions.logger.log(`width: `, width);
functions.logger.log(`height: `, height);