【发布时间】:2018-06-30 18:43:19
【问题描述】:
我正在寻找获取多个网站 IP 并将它们输出为 "domain.com:","1.1.1.1" 的最佳方法,以实现这一点我正在考虑使用 nslookup(不确定是否是最佳选择,但我不想要使用 ping)
好吧,我正在尝试类似的东西:
for domain in $(cat domains.txt)
do
nslookup $domain 8.8.8.8 | awk '/Address: ([[:digit:]]+\.){3}/{gsub(/\.$/,"",$1); printf "\"%s\",\"%s\"\n",$1,$NF}'; done
有了这个,我得到了这个输出:
"Address:","64.233.190.101"
"Address:","64.233.190.138"
"Address:","64.233.190.100"
"Address:","64.233.190.139"
"Address:","64.233.190.113"
"Address:","64.233.190.102"
"Address:","98.137.246.8"
"Address:","98.138.219.231"
"Address:","72.30.35.9"
"Address:","72.30.35.10"
"Address:","98.138.219.232"
"Address:","98.137.246.7"
"Address:","93.184.216.34"
预期输出
"google.com","64.233.190.101"
"google.com","64.233.190.138"
"google.com","64.233.190.100"
"google.com","64.233.190.139"
"google.com","64.233.190.113"
"google.com","64.233.190.102"
"yahoo.com","98.137.246.8"
"yahoo.com","98.138.219.231"
"yahoo.com","72.30.35.9"
"yahoo.com","72.30.35.10"
"yahoo.com","98.138.219.232"
"yahoo.com","98.137.246.7"
"example.com","93.184.216.34"
domains.txt 内容:
google.com
yahoo.com
example.com
我试图这样做,但我无法在输出的"domain.com", 下获得正确的域。
我不确定是使用 $domain 还是 awk,任何人都可以帮助我获得正确的语法。请注意,我需要在 "domain.com", 中请求域,而不是 nslookup 中的 Name:
谢谢。
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