Django inlineformset 不保存 ForeignKey 字段答案

【问题标题】：Django inlineformset does not save ForeignKey fieldDjango inlineformset 不保存 ForeignKey 字段
【发布时间】：2014-07-16 03:31:42
【问题描述】：

所以我正在测试 Django 中的 inlineformset 功能，到目前为止有以下代码：

应用程序名称：示例

models.py

from django.db import models
from django.core.urlresolvers import reverse

class Recipe(models.Model):
    pub_date = models.DateTimeField('Date Published', auto_now_add= True)
    title = models.CharField(max_length=200)
    instruction = models.TextField()

    def __unicode__(self):
        return self.title

    def get_absolute_url(self):
        return reverse('recipe_edit', kwargs={'pk': self.pk})


class Ingredient(models.Model):
    recipe = models.ForeignKey(Recipe, related_name="ingredients")
    ingredient = models.CharField(max_length=255)

    def __unicode__(self):
        return self.recipe_id

    def get_absolute_url(self):
        return reverse('ingredient_edit', kwargs={'pk': self.recipe_id})

forms.py

from django import forms
from models import Recipe, Ingredient
from django.forms.models import inlineformset_factory

MAX_INGREDIENTS = 5

IngredientFormSet = inlineformset_factory(
    Recipe,
    Ingredient,
    can_delete=False,
    extra=MAX_INGREDIENTS
)


class UserSubmittedRecipeForm(forms.ModelForm):
    class Meta:
        model = Recipe
        exclude = ('pub_date',)

views.py

def recipe_create(request, template_name='example/recipe_form.html'):
    if request.POST:
        form = UserSubmittedRecipeForm(request.POST)
        if form.is_valid():
            recipe = form.save(commit=False)
            ingredient_formset = UserSubmittedRecipeForm(request.POST, instance=recipe)
            if ingredient_formset.is_valid():
                recipe.save()
                ingredient_formset.save()
                return redirect('recipe_list')
    else:
        form = UserSubmittedRecipeForm()
        ingredient_formset = IngredientFormSet(instance=Recipe())
    return render(request, template_name, {
        "form": form,
        "ingredient_formset": ingredient_formset
    }, context_instance=RequestContext(request))

查看版本 2 这也不起作用。

def recipe_create(request, template_name='example/recipe_form.html'):
    if request.POST:
        form = UserSubmittedRecipeForm(request.POST)
        if form.is_valid():
            created_recipe = form.save()
            ingredient_formset = UserSubmittedRecipeForm(request.POST, instance=created_recipe)
            if ingredient_formset.is_valid():
                ingredient_formset.save()
                return redirect('recipe_list')
    else:
        form = UserSubmittedRecipeForm()
        recipe = Recipe()
        ingredient_formset = IngredientFormSet(instance=recipe)
    return render(request, template_name, {
        "form": form,
        "ingredient_formset": ingredient_formset
    }, context_instance=RequestContext(request))

我遇到的问题是每次提交表单时都没有保存成分模型中的“成分”字段。

没有显示错误。配方模型中的其余字段已正确保存。

有人知道这是为什么吗？

【问题讨论】：

标签： python django inline-formset

【解决方案1】：

应该
ingredient_formset = UserSubmittedRecipeForm(request.POST, instance=created_recipe)
是
ingredient_formset = IngredientFormSet(request.POST, instance=created_recipe)?

如果这是问题所在，那么您在两个视图中都遇到了问题。

【讨论】：

【解决方案2】：

第 2 版视图中有错字。检查这是否解决了您的问题

Views.py 版本 2：

   def recipe_create(request, template_name='example/recipe_form.html'):
    if request.POST:
        form = UserSubmittedRecipeForm(request.POST)
        if form.is_valid():
            created_recipe = form.save()
            #There was a typo here
            ingredient_formset = IngredientFormSet(request.POST, instance=created_recipe)
            if ingredient_formset.is_valid():
                ingredient_formset.save()
                return redirect('recipe_list')
    else:
        form = UserSubmittedRecipeForm()
        recipe = Recipe()
        ingredient_formset = IngredientFormSet(instance=recipe)
    return render(request, template_name, {
        "form": form,
        "ingredient_formset": ingredient_formset
    }, context_instance=RequestContext(request))

【讨论】：

感谢@gmfreak，您的回答也正确，因为 neRok 首先发布了它，所以我必须接受他的回答。