频繁序列化使用 Xml 序列化的正确方法

Question

I have a list box that when an item is selected or deselected I want to save the changes to an x​​ml file (so it is always up-to-date on the file and the user does not need a "save" button )。

在测试时我偶尔会遇到这个 IOException：

进程无法访问文件“C:\MyPath\MyFile.xml”，因为它正被另一个进程使用。

这是我的 XML 序列化代码：

// Save an object out to the disk
public static void SerializeObject<T>(this T toSerialize, String filename)
{
    XmlSerializer xmlSerializer = new XmlSerializer(toSerialize.GetType());
    TextWriter textWriter = new StreamWriter(filename);

    xmlSerializer.Serialize(textWriter, toSerialize);
}

// Load an object from the disk
private static T DeserialzeObject<T>(String filename) where T : class
{
    XmlSerializer xmlSerializer = new XmlSerializer(typeof(T));

    try
    {
        TextReader textReader = new StreamReader(filename);
        return (T)xmlSerializer.Deserialize(textReader);
    }
    catch (FileNotFoundException)
    { }

    return null;
}

这就是它的名称：

// Save off the list because the visibility has changed
public void WorkItemColumnTypeOnVisibleChanged(int fieldID, Visibility visibility)
{
    ColumnFields.SerializeObject(ColumnFields.GetSerializeFilename());
}

反序列化是给出错误的那个：

WorkItemColumnTypes savedVersion = DeserialzeObject<WorkItemColumnTypes>(result.GetSerializeFilename());

有没有办法优化我与文件的连接，这样我就不会被自己绊倒？

Answer 1

也许您需要在序列化和反序列化方法中对TextWriter 对象调用Close？或者，也可以使用using 构造在块的末尾强制处理。

例子：

// Save an object out to the disk
public static void SerializeObject<T>(this T toSerialize, String filename)
{
    XmlSerializer xmlSerializer = new XmlSerializer(toSerialize.GetType());
    using(TextWriter textWriter = new StreamWriter(filename))
    {

        xmlSerializer.Serialize(textWriter, toSerialize);
    }
}

// Load an object from the disk
private static T DeserialzeObject<T>(String filename) where T : class
{
    XmlSerializer xmlSerializer = new XmlSerializer(typeof(T));

    try
    {
        using(TextReader textReader = new StreamReader(filename))
        {
            return (T)xmlSerializer.Deserialize(textReader);
        }
    }
    catch (FileNotFoundException)
    { }

    return null;
}