【发布时间】:2015-08-31 12:16:48
【问题描述】:
所以我创建了新的 Maven 模块。我使用“maven-archetype-webapp”来创建它。当我在 index.jsp 中执行普通文本时,一切正常。但我也想做servlet。
我将很快写下我是如何创建它的。我右键单击我的模块和新建-> Servlet。 Java包:pl.marek,类名:MyServlet,后来我选择了“doPost”和“doGet”。这是我的文件的样子:
index.jsp
<%@page import="java.util.Date"%>
<%@page import="pl.marek.countriesmapper.reader.*" %>
<%@page import="pl.marek.countriesmapper.preparer.*" %>
<%@page import="pl.marek.countriesmapper.country.*" %>
<%@ page language="java" contentType="text/html; charset=US-ASCII"
pageEncoding="US-ASCII"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=US-ASCII">
<title>Hello</title>
</head>
<body>
<form action="MyServlet">
Please enter your Username: <input type="text" name="username" size="20px"> <br>
Please enter your Password: <input type="text" name="password" size="20px"> <br><br>
<input type="submit" value="submit">
</form>
</body>
</html>
MyServlet.java
package pl.marek;
import java.io.IOException;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
/**
* Servlet implementation class MyServlet
*/
public class MyServlet extends HttpServlet {
private static final long serialVersionUID = 1L;
/**
* @see HttpServlet#HttpServlet()
*/
public MyServlet() {
super();
// TODO Auto-generated constructor stub
}
/**
* @see HttpServlet#doGet(HttpServletRequest request, HttpServletResponse response)
*/
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
String username = request.getParameter("username");
String password = request.getParameter("password");
PrintWriter out = response.getWriter();
out.println (
"<!DOCTYPE html PUBLIC \"-//W3C//DTD HTML 4.01 Transitional//EN\" +" +
"http://www.w3.org/TR/html4/loose.dtd\">\n" +
"<html> \n" +
"<head> \n" +
"<meta http-equiv=\"Content-Type\" content=\"text/html; " +
"charset=ISO-8859-1\"> \n" +
"<title> Crunchify.com JSP Servlet Example </title> \n" +
"</head> \n" +
"<body> <div align='center'> \n" +
"<style= \"font-size=\"12px\" color='black'\"" + "\">" +
"Username: " + username + " <br> " +
"Password: " + password +
"</font></body> \n" +
"</html>"
);
}
}
/**
* @see HttpServlet#doPost(HttpServletRequest request, HttpServletResponse response)
*/
protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
// TODO Auto-generated method stub
doGet(request, response);
}
}
Web.xml
<!DOCTYPE web-app PUBLIC
"-//Sun Microsystems, Inc.//DTD Web Application 2.3//EN"
"http://java.sun.com/dtd/web-app_2_3.dtd" >
<web-app>
<display-name>Archetype Created Web Application</display-name>
<servlet>
<servlet-name>MyServlet</servlet-name>
<display-name>MyServlet</display-name>
<description></description>
<servlet-class>pl.marek.MyServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>MyServlet</servlet-name>
<url-pattern>MyServlet</url-pattern>
</servlet-mapping>
</web-app>
这是我的项目的照片:
当我点击提交时,我有地址:localhost:8080/WebAplication/MyServlet?username=test123&password=test321
但在网页上我有:
HTTP Status 404 -
type Status report
message
description The requested resource is not available.
Apache Tomcat/7.0.47
也许有人知道我做错了什么? :/
@编辑
我在 web.xml 中删除了“/”,现在我有了这个:
HTTP Status 500 - Error instantiating servlet class pl.marek.MyServlet
错误 500 已解决,但我仍然有状态 404:/
@edit2
我做了 SaviNuclear 的内容,但仍然出现 404 错误:/
@edit3
问题解决了。我必须创建 src/java 而不是 src/resources。
【问题讨论】:
-
username=test123$password=test321??那应该是username=test123&password=test321? -
是的,我的错,因为我没有复制它而是手动写的:P
-
如果您访问没有 Get 参数的 Servlet,您是否也会得到 404? localhost:8080/WebAplication/MyServlet
-
是的,我仍然有错误 404 状态。
-
你的servlet在tomcat中成功部署了吗?