【发布时间】:2015-03-10 16:59:39
【问题描述】:
我正在做一个关于休眠、jsp 和 servlet 以及数据库的最终项目 我的主题是制作食谱的网络应用程序
现在,我要注册
我用这个方法检查uname是否已经被使用(这个方法很好用,没有错误)
public boolean unameMember (String namaTabel,String uname)
{
this.session = NewHibernateUtil.getSessionFactory().openSession();
ArrayList<Member> hasil = null;
boolean uyey = true;
Transaction tx = session.beginTransaction();
Query q = session.createQuery("from "+namaTabel);
hasil = (ArrayList<Member>) q.list();
for (Member m : hasil)
{
if(m.getIdMember().equals(uname))
uyey=false;
}
session.close();
return uyey;
}
这是 register.jsp 的表单
<form action="MemberServlet" method="post" id="regform">
<div class="form" >
<div class="form_row">
<label>Username:</label>
<input type="text" name="id_member" required />
</div>
<div class="form_row">
<label>Password:</label>
<input type="password" name="pw" required />
</div>
</div>
<div class="form_row">
<label>Name:</label>
<input type="text" name="nama" required/>
</div>
<div class="form_row">
<label>Alamat:</label>
<input type="text" name="alamat" required/>
</div>
<input type="submit" value="Register" />
</div>
</form>
现在是 MemberServlet.java 中的问题
String id_member = request.getParameter("id_member");
String pw = request.getParameter("pw");
String nama = request.getParameter("nama");
String alamat = request.getParameter("alamat");
DataAkses da = new DataAkses();
try {
out.println("<html>");
out.println("<head>");
out.println("</head>");
out.println("<body>");
if (da.unameMember("Member", nama)) {
da.addMember(id_member, pw, nama, alamat);
out.println("<script type=\"text/javascript\">");
out.println("alert('You can sign in with your new account');");
out.println("</script>");
request.getRequestDispatcher("home.jsp").include(request, response);
} else {
out.println("<script type=\"text/javascript\">");
out.println("alert('User or password incorrect');");
out.println("location='register.jsp';");
out.println("</script>");
} } catch (Exception e) {
out.println("<html>");
out.println("<head>");
out.println("</head>");
out.println("</b>");
out.println("<body>");
out.println("<center>");
out.println("<h1>haha ga bisa </h1>");
out.println("</center>");
out.println("</body>");
e.printStackTrace();
}
如果我想添加具有不同 unname 的成员,它工作得很好 除此以外 它总是在 catch 异常中显示“haha ga bisa”
请帮帮我
【问题讨论】:
-
能否请您从控制台提供您的错误堆栈跟踪?
-
如何显示错误堆栈跟踪?对不起,我是编程初学者
标签: java hibernate jsp servlets