如果他们获得默认值，我正在尝试让我的开关盒再次循环

Question

    //Choice of choosing a dog or a cat

     String pet = input.next();

    switch (pet.charAt(0)) {
        case 'a' -> {
            System.out.println("What is your dog's name? ");
            String dogsName = input.next();
            System.out.println("Your Character's Name is: " + playerName + "\nYour Pet's Name is: " + dogsName);
        }
        case 'b' -> {
            System.out.println("What is your cat's name? ");
            String catsName = input.next();
            System.out.println("Character Name: " + playerName + "\nPet Name: " + catsName);
        }
        default -> System.out.println("That is not a valid option. Please choose again.");
    }

   input.close();

}

我找不到可以将其带回案例 a 并重复使用的循环，直到用户使用其中一个选项回答，任何帮助都会很棒！谢谢

Answer 1

使用do while循环是一种简单的解决方法。

我使用了变量repeat来检查，是否需要再次请求输入

另外，请注意，现在即使我添加另一个案例（比如 case 'c'），我也不需要修改 do while 循环的条件

boolean repeat;
do {
    String pet = input.next();
    repeat = false;
    switch (pet.charAt(0)) {
        case 'a' -> {
            System.out.println("What is your dog's name? ");
            String dogsName = input.next();
            System.out.println("Your Character's Name is: " + playerName + "\nYour Pet's Name is: " + dogsName);
        }
        case 'b'-> {
            System.out.println("What is your cat's name? ");
            String catsName = input.next();
            System.out.println("Character Name: " + playerName + "\nPet Name: " + catsName);
        }
        default: System.out.println("That is not a valid option. Please choose again.");
        repeat = true;
    }
} while(repeat);
input.close();

Answer 2

循环是很好的解决方案，但您也可以在 java 中使用 Recessive 方法。

public static void main(String[] args) {
    
        Scanner input = new Scanner(System.in);
    
    
        System.out.println("    Welcome To The Choices Game...    ");
        System.out.println("Please enter your name: " );
    
        String playerName = input.nextLine();
    
        System.out.println("What is " + playerName + "'s" + " favorite pet?");
        System.out.println("a. Dog \nb. Cat");
    
        //Choice of choosing a dog or a cat
    
        method();
   
    
      input.close();
    
 }

public void method()
{

         String pet = input.next();
    
        switch (pet.charAt(0)) {
            case 'a' -> {
                System.out.println("What is your dog's name? ");
                String dogsName = input.next();
                System.out.println("Your Character's Name is: " + playerName + "\nYour Pet's Name is: " + dogsName);
            }
            case 'b' -> {
                System.out.println("What is your cat's name? ");
                String catsName = input.next();
                System.out.println("Character Name: " + playerName + "\nPet Name: " + catsName);
            }
            default -> System.out.println("That is not a valid option. Please choose again.");
            method();
        }
       
}

Answer 3

要循环整个 switch-case 部分，您可以尝试将其置于 do-while 循环中。至于与 do-while 块一起使用的条件，您可以尝试：- do {...}while(pet.charAt(0)!='a' || pet.charAt(0)!='b');

我在下面为您提供一个可能的解决方案：-

   public static void main(String[] args) {

    Scanner input = new Scanner(System.in);


    System.out.println("    Welcome To The Choices Game...    ");
    System.out.println("Please enter your name: " );

    String playerName = input.nextLine();

    System.out.println("What is " + playerName + "'s" + " favorite pet?");
    System.out.println("a. Dog \nb. Cat");

    //Choice of choosing a dog or a cat

    do{
     String pet = input.next();

    switch (pet.charAt(0)) {
        case 'a' -> {
            System.out.println("What is your dog's name? ");
            String dogsName = input.next();
            System.out.println("Your Character's Name is: " + playerName + "\nYour Pet's Name is: " + dogsName);
            break;}
        case 'b' -> {
            System.out.println("What is your cat's name? ");
            String catsName = input.next();
            System.out.println("Character Name: " + playerName + "\nPet Name: " + catsName);
            break;}
        default -> System.out.println("That is not a valid option. Please choose again.");
    }
   
}while(pet.charAt(0)!='a' && pet.charAt(0)!='b');

  input.close();

}